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Lynna [10]
3 years ago
13

Vector L is 303 m long in a

Physics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

584.32m

Explanation:

Firstly, we need to find the x and y components of each vector.

x-component for vector L=303cos205°=-274.61

y-component for vector L=303sin205°=-128.05

x-component for vector M=555cos105°=-143.64

y-component for vector M=555sin105°=536.09

Since it's the vector sum, we add the x and y components of each vector.

Resultant vector x-component -274.61+(-143.64)=-418.25

Resultant vector y-component -128.05+536.09=408.04

Now, to find the magnitude, we use the formula \sqrt{x^{2}+y^{2}}

sqrt(-418.25^2+408.04^2)=584.32m

Check my work for errors just in case.

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Answer:B

Explanation:

6 0
3 years ago
How much work does it take to lift 345 boxes to a height of 6.00 m of each box has a mass of 7.89 kg
Art [367]

Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied or Weight and d is distance

Also Force = Weight = mass × acceleration due to gravity.

Since gravity is acting on the boxes as it been lift

W = Weight × height from ground level

W = mg × d

Where m is mass of the boxes, g is accelration due to gravity( g = 9.8m/s² ) and d is distance from ground level.

Given the data in the question;

  • Since each box has a mass of 7.89 kg
  • Mass of the 345 boxes = 345 × 7.89 kg = 2722.05kg
  • Distance or height d = 6.0m
  • Work done W = ?

To determine the work done, we substitute our values into the expression above.

W = mg × d

W = 2722.05kg × 9.8m/s² × 6.0m

W = 160056.5kgm²/s²

W = 160056.5J

W = 1.6 × 10⁵J

Therefore,  Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

Learn more about work done here: brainly.com/question/26115962

3 0
2 years ago
On a cross-country trip, a couple drives 500 mi in 10 h on the first day, 380 mi in 8.0 h on the second day, and 600 mi in 15 h
Zepler [3.9K]

We know that the average speed is simply the ratio of the total distance travelled over the total duration of the trip.

total distance = 500 mi + 380 mi + 600 mi

total distance = 1,480 mi

 

total time = 10 h + 8 h + 15 h

total time = 33 h

 

So the average speed is therefore:

average speed = 1,480 mi / 33 h

<span>average speed = 44.85 mi / h</span>

8 0
3 years ago
4. What is the acceleration of a plane that changes velocity from 75 m/s to
kompoz [17]

Answer:

a =  \frac{v - u}{t}  \\ s =  \frac{ {v}^{2} -  {u}^{2}  }{2a}

Explanation:

Apply SUVAT

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What type of data allows geologists to know what rock layers lie underneath Minnesota?
mrs_skeptik [129]
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