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3 years ago

Vector L is 303 m long in a

Physics

1 answer:

Soloha48 [4]3 years ago

6 0

Answer:

584.32m

Explanation:

Firstly, we need to find the x and y components of each vector.

x-component for vector L=303cos205°=-274.61

y-component for vector L=303sin205°=-128.05

x-component for vector M=555cos105°=-143.64

y-component for vector M=555sin105°=536.09

Since it's the vector sum, we add the x and y components of each vector.

Resultant vector x-component -274.61+(-143.64)=-418.25

Resultant vector y-component -128.05+536.09=408.04

Now, to find the magnitude, we use the formula $\sqrt{x^{2}+y^{2}}$

sqrt(-418.25^2+408.04^2)=584.32m

Check my work for errors just in case.

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