Complete Question
A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?
Answer:
The values is
Explanation:
From the question we are told that
The distance it travels eastward is
The distance it travel towards the southeast is
The distance it travel towards the south is
Let x-axis be east
y-axis south
z-axis into the ground
The angle made between east and south is
The displacement toward x-axis is
The displacement toward the y-axis is
Now the overall displacement of the rat is mathematically evaluated as
Answer:
5.56 A
Explanation:
From the question,
Q = it.............. Equation 1
Where Q = charges, i = current, t = time.
Make i the subject of the equation
i = Q/t.............. Equation 2
Given: Q = 200 coulombs, t = 0.6 minutes = (0.6×60) seconds
Substitite these values into equation 2
i = 200/(0.6×60)
i = 5.56 A
Hence the magnitude of the current flowing through the circuit is 5.56 A
Answer:
Max height= 36000 meters
Total Time = 120 seconds
Explanation:
0 = U - at
U = at
U= 20*60
U= 1200 m/s
MAX altitude would be
(U²Sin²tita)/2g
Max height= 1200² *( SIN90)²/(2*20)
Time of FLIGHT
2 * 1200/20
2400/20
120 sec
onds
In order to find the displacement of something, you can calculate it by subtracting the initial distance from the final distance.
7-5 =2
so the mouse would’ve walked a displacement of 2cm
The height of a wave or the amount of air the wave carries is the amplitude air
Air is the word
Hope I helped