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pantera1 [17]
1 year ago
8

A solution is made by dissolving 3.14 g of NaCl in 79.9 mL of water. What is the concentration of sodium chloride in units of we

ight/volume percent? Group of answer choices 3.78% (w/v) NaCl 96.1% (w/v) NaCl 3.93% (w/v) NaCl 0.0393% (w/v) NaCl
Chemistry
1 answer:
Trava [24]1 year ago
6 0

The concentration of sodium chloride in units of weight/volume percent is 3.93g/ml

Given that

3.93 (w/v) NaCl

Weight NaCl = 3.14g

Volume of water = 79.9mL

W/V is usually represented in g/mL, so no need to change anything

3.14g/79.9mL *100 = 3.93 g/mL (%)

One mole of NaCl contains 6.022 x 10 23 NaCl formula units.

• Use the mole quantity to count formulas by weighing them.

• Mass of a mole of particles = mass of 1 particle x 6.022 x 1023

• The mass of an atom in amu is numerically the same

as the mass of one mole of atoms of the element in grams.

• One atom of sulfur has a mass of 32.07 amu;

one mole of S atoms has a mass of 32.07 g.

Mass of 1 H atom: 1.008 amu x 1.661 x10-24 g/amu = 1.674 x10-24 g

Mass of 1 mole of H atoms:

1.674 x10-24g/H atom x 6.022 x1023H atoms = 1.008 g

Learn more about Weight / volume Percentage here

brainly.com/question/14296094

#SPJ4

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I hope my answer has come to your help. God bless and have a nice day ahead!
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First, we should find the mole of KOH:
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Now, let's find the volume of HNO3 soln:
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I hope this helps in any way :)

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