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pantera1 [17]
2 years ago
8

A solution is made by dissolving 3.14 g of NaCl in 79.9 mL of water. What is the concentration of sodium chloride in units of we

ight/volume percent? Group of answer choices 3.78% (w/v) NaCl 96.1% (w/v) NaCl 3.93% (w/v) NaCl 0.0393% (w/v) NaCl
Chemistry
1 answer:
Trava [24]2 years ago
6 0

The concentration of sodium chloride in units of weight/volume percent is 3.93g/ml

Given that

3.93 (w/v) NaCl

Weight NaCl = 3.14g

Volume of water = 79.9mL

W/V is usually represented in g/mL, so no need to change anything

3.14g/79.9mL *100 = 3.93 g/mL (%)

One mole of NaCl contains 6.022 x 10 23 NaCl formula units.

• Use the mole quantity to count formulas by weighing them.

• Mass of a mole of particles = mass of 1 particle x 6.022 x 1023

• The mass of an atom in amu is numerically the same

as the mass of one mole of atoms of the element in grams.

• One atom of sulfur has a mass of 32.07 amu;

one mole of S atoms has a mass of 32.07 g.

Mass of 1 H atom: 1.008 amu x 1.661 x10-24 g/amu = 1.674 x10-24 g

Mass of 1 mole of H atoms:

1.674 x10-24g/H atom x 6.022 x1023H atoms = 1.008 g

Learn more about Weight / volume Percentage here

brainly.com/question/14296094

#SPJ4

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3 years ago
Chandra wants to know how many moles are contained in 150.0 g ccl4 (carbon tetrachloride). what quantity of ccl4 should she use
Fynjy0 [20]

The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mole of CCl₄</h3>
  • Mass of CCl₄ = 30 g
  • Molar mass of CCl₄ = 12 + (35.5×4) = 154 g/mol
  • Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 150 / 154

Mole of CCl₄ = 0.974 mole

Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.

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8 0
2 years ago
How many joules of energy are made by the loss of 100kg of mass using the formula E=mc2? please help!!!
asambeis [7]

Answer:

E = 3 × 10¹⁰ J

Explanation:

Mass, m = 100 kg

We need to find energy made by the loss of 100 kg of mass. The formula between the mass and energy is given by :

E = mc²

Where c is speed of light

Putting all the values, we get :

E = 100 kg × (3×10⁸ m/s)²

= 3 × 10¹⁰ J

So, the required energy is 3 × 10¹⁰ J.

6 0
3 years ago
Butane, ch3-ch2-ch2-ch3, is a hydrocarbon fuel used in lighters. how many moles of molecules are there in a 350. gram sample of
Galina-37 [17]
<span>6.03 moles.



1 molecule of butane contains 4 carbon atoms and ten hydrogen atoms.

The molar mass is 4 times the atomic mass of carbon, 12 g/mol, plus 10 times the atomic weight of hydrogen, 1 g/mol.

Molar mass = 4 * 12 g/mol + 10 * 1 g/mol = 58 g/mol.

This means that 1 mole of butane has a mass of 58 g.

To figure out how many moles are in a sample of butane, divide the mass of sample in grams by 58 grams

Number of moles in sample = 350 g / 58 g/mol = 6.03 moles.</span>
3 0
3 years ago
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