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yuradex [85]
3 years ago
11

Why is it a good idea to explore the health and fitness field in terms of career

Physics
2 answers:
KIM [24]3 years ago
7 0
D xrxtxtxt t txt yhhgedd Ed ggdfn
elena-14-01-66 [18.8K]3 years ago
4 0

Answer: I think the answer is option D.

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A party shop delivers helium-filled balloons to homes and businesses. The owners realize from experience that on hot summer days
kvasek [131]

Answer:As the temperature increases, the helium in the ballon expands.

Explanation:

I took the quiz already

6 0
2 years ago
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What is the purpose of experimentation in a research study
Nat2105 [25]
Hello,

The answer is to "prove your hypothesis".

Reason:

Researchers do experiments to prove there hypothesis they will most likely do the experiment a few times in older to have the conclusion valid therefore proving his or her experiment. 

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
6 0
3 years ago
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An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

x = V*t = -8\frac{m}{s} *3s = -24m

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

v^2 = v_0^2 + 2a*d

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s

Then, the time of the second phase will be:

t_2 = 9s - t_1 = 9s - 1.143s = 7.857s

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

x = \frac{1}{2}a*t^2 + v_0*t + x_0

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m

So, the total distance covered by this object in meters will be the sum of all the distances we found:

x_total = 24m + 4.57m + 216.07m = 244.64m

8 0
2 years ago
Two friends whisper at a volume of 20 decibels. Later, they converse at a volume of 40 decibels.
Yuki888 [10]
40 dB is 20 dB more power than 20 dB is. 20 dB more means 100 times as much.
4 0
2 years ago
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Rope BCA passes through a pulley at point C and supports a crate at point A. Rope segment CD supports the pulley and is attached
RUDIKE [14]

Answer:

Wmax = 63.65 ≈ 64 lb

Explanation:

6 0
3 years ago
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