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2 years ago

9

Help meee please i need help

2 answers:

Dmitriy789 [7]2 years ago

6 0

Answer:

81pi

Step-by-step explanation:

You are asking yourself the area of pi*r^2 could with r as 9. pi*9^2. solve and you get 81pi :D

Talja [164]2 years ago

5 0

The answer is 81 pi (81 3.14)

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How to solve this??<br><br> (r^-7b^-8) ^0<br> -------------<br> (t^-4w)

professor190 [17]

keeping in mind that anything raised at the 0 power, is 1, with the sole exception of 0 itself.

$\bf ~~~~~~~~~~~~\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad a^n\implies \cfrac{1}{a^{-n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\cfrac{(r^{-7}b^{-8})^0}{t^{-4}w}\implies \cfrac{1}{t^{-4}w}\implies \cfrac{1}{t^{-4}}\cdot \cfrac{1}{w}\implies t^4\cdot \cfrac{1}{w}\implies \cfrac{t^4}{w}$

6 0

3 years ago

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How do you write 9 1/10 as a percent

IrinaVladis [17]

Answer:910%

Step-by-step explanation:

Each whole number is 100% and each 1/10 is 10% percent so it is 910%vote brainiest please.

8 0

3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago

Calculate the slope of the line

malfutka [58]

Answer:

-5/4 or -1.25

Step-by-step explanation:

the points are (-6, -3) and (-2, -8)

the formula for slope is y2-y1/x2-x1

y2 is -8

y1 is -3

x2 is -2

x1 is -6

(-8+3)/(-2+6)

(-5)/(4)

-5/4 or -1.25

3 0

3 years ago

Help me to solve problem pless

sergejj [24]

Answer:

a:

5 x -3 +6

= 5 x 6 + -3

= 30 + -3

= 27

8 0

2 years ago

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