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ASHA 777 [7]
2 years ago
6

Car A starts from rest at t = 0 and travels along a straight road with a constant acceleration of 6 ft/s2 until it reaches a spe

ed of 80 ft/s. Afterwards it maintains this speed. Also, when t = 0, car B located 6000 ft down the road is traveling towards A at a constant speed of 60 ft/s. Determine the distance traveled by car A when they pass each other.
Engineering
1 answer:
taurus [48]2 years ago
4 0

The distance traveled by car A when they pass each other is 1071m

<h3>Calculations and Parameters</h3>

Given:

t=0

constant acceleration= 6 ft/s^2

speed= 80 ft/s^2

S_A= \frac{at1^2}{2} + V_At\\S_B= V_B (t1 +t)

= 2 * (\frac{27}{2})^{2}/2 + 27 * 32.9

= 1071m

Read more about distance here:

brainly.com/question/2854969

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