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olga55 [171]
3 years ago
15

WILL AWARD BRAINLIEST

Engineering
1 answer:
ValentinkaMS [17]3 years ago
3 0
I think it is C because if have to send it to someone you would want them to be able to open it
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Define cooling tower "range" as it applies to cooling towers.
Arlecino [84]

Answer:

The answer to the range of a cooling tower is the difference between the temperature of the water going in and the temperature of the water going out of the tower.

Explanation:

Cooling towers are used to cool a stream of water using the air of the environment where it's placed or installed. In theory, the lowest temperature the water can be cooled to would be the wet bulb temperature (temperature of the air going in the cooling tower). The range would be the difference (R=Ti-To) between the temperature of the hot water going in and the cooler water going out.

8 0
3 years ago
Which best describes the body in terms of simple machines?
alex41 [277]

Answer:B

Explanation:

5 0
4 years ago
Consider steady heat transfer through the wall of a room in winter. The convection heat transfer coefficient at the outer surfac
AveGali [126]

The heat transfer which is in steady state, the heat transfer rate to the wall is equal to the wall.

<u>Explanation:</u>

  • The convection transfer of heat to the wall is

         Q=h A\left(T_{s}-T_{f}\right)

  • Here, T_{S} is the temperature of solid surface, T_{f} is the temperature of moving fluid stream which is adjacent of solid surface, h is the heat transfer coefficient.
  • The coefficient of convection heat transfers outer surface contains 3 times to the inner surface which experience smaller drop of temperature for 3 times that compares to inner surface.
  • Hence, the temperatures outer surface get close to the surroundings of air temperature.
6 0
3 years ago
Three identical fatigue specimens (denoted A, B, and C) are fabricated from a nonferrous alloy. Each is subjected to one of the
Law Incorporation [45]

Answer:

B A and C

Explanation:

Given:

Specimen         σ_{max}                      σ_{min}

A                       +450                      -150

B                       +300                      -300

C                       +500                      -200

Solution:

Compute the mean stress

σ_{m} =  (σ_{max}  +  σ_{min})/2

σ_{mA} =  (450 + (-150)) / 2

       =  (450 - 150) / 2  

       = 300/2

σ_{mA} = 150 MPa

σ_{mB}  = (300 + (-300))/2

        = (300 - 300) / 2

        = 0/2  

σ_{mB}  = 0 MPa

 

σ_{mC}  = (500 + (-200))/2

        = (500 - 200) / 2

        = 300/2

σ_{mC}  = 150 MPa  

Compute stress amplitude:

σ_{a} =  (σ_{max}  -  σ_{min})/2    

σ_{aA} =  (450 - (-150)) / 2

       =  (450 + 150) / 2

       = 600/2

σ_{aA} = 300 MPa

σ_{aB} =  (300- (-300)) / 2

       =  (300 + 300) / 2

       = 600/2

σ_{aB}  = 300 MPa

σ_{aC}  = (500 - (-200))/2

        = (500 + 200) / 2

        = 700 / 2

σ_{aC}   = 350 MPa

From the above results it is concluded that the longest  fatigue lifetime is of specimen B because it has the minimum mean stress.

Next, the specimen A has the fatigue lifetime which is shorter than B but longer than specimen C.

In the last comes specimen C which has the shortest fatigue lifetime because it has the higher mean stress and highest stress amplitude.

7 0
4 years ago
Assume that a specific hard disk drive has an average access time of 16ms (i.e. the seek and rotational delay sums to 16ms) and
djyliett [7]

Answer:

Average access time for a hard disk = 11.38 ms

Explanation:

See attached pictures for step by step explanation.

5 0
4 years ago
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