Answer:
The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Explanation:
Given;
distance between the parallel wires, r = 5.0 cm = 0.05 m
current in the first wire, I₁ = 1.65 A
current in the second wire, I₂ = 3.25 A
The magnitude of the force per unit length between the two wires is calculated as follows;
Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Explanation:
When there is a constant unbalanced force applied in the same direction as the motion, speed will increase and acceleration will remain constant. When there is an increasing unbalanced force applied in the same direction as the motion, speed will increase and acceleration will increase.
According to newton's 2nd law
F = ma
F ∝ a
meaning when F increases , a increases and vice versa
Answer:
D
Explanation:
plz plz this answer is good i hope
Answer:
D. it demonstrates electromagnetism.
Explanation:
If a wire carrying current causes the needle of a compass to move, it is an example of electromagnetism.
The interaction between electric and magnetic fields is termed electromagnetism.
- Electromagnetic interaction is usually induced between a wire and bar magnet.
- With right set up magnetic and electrical fields can be induced using a magnet and current carrying wire.
THere is a standard relationship that gives this result where the capacity of the capacitor is used:
.
We know though that Q/c=V and thus we can use the relationship:
E=Q*V/2 where we have just substituted in. If we also take into account that Q=VC, we can also get that E=V^2*C/2.
We are given the charge and the potential, so the best expression to use is the middle one.
Substituting, we get that E=1/2*8*10^(-10)*20=8*10^(-9).
The answer is B
