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OLga [1]
2 years ago
13

An object has 22.4 kg•m/s of

Physics
2 answers:
Bad White [126]2 years ago
5 0

Answer:

22.4\:\mathrm{kg\cdot m/s}

Explanation:

Momentum is given by p=mv.

Let p_1 be the initial momentum of the object:

p_1=m\cdot v=22.4

If we doubled the mass, the new mass would be 2\cdot m, and if we halved the velocity, the new velocity would be \frac{1}{2}\cdot v.

Therefore, the final momentum would be:

p_f=2\cdot m\cdot \frac{1}{2}\cdot v=m\cdot v=\fbox{$22.4\:\mathrm{kg\cdot m/s}$}..

SSSSS [86.1K]2 years ago
4 0

Answer:

the answer is 22.4 kg*m/s

Explanation:

Such a bizarre unit!

Acellus is cool. I receive and share knowledge almost every day.

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A ball rolls off the edge of a table with a fairly large horizontal velocity. Which of the following statements are true? (Selec
Degger [83]

Answer:

A.The vertical velocity is constantly increasing as the ball falls.

B.The horizontal velocity does not noticeably change as the ball falls.

G.The horizontal velocity does not affect how long it will take the ball to fall to the floor.

H.The velocity vector of the ball changes as it travels through the air.

Explanation:

As the ball is projected horizontally so here the vertical component of the velocity is zero

So the time to reach the ground is given as

H = \frac{1}{2} gt^2

so we will have

t = \sqrt{\frac{2H}{g}}

so this is the same time as the ball is dropped from H height

Since there is no force in horizontal direction so its horizontal velocity will always remain constant while vertical velocity will change at constant rate which is equal to acceleration due to gravity.

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4 0
3 years ago
You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi
Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0
3 years ago
A student shoots a spitball with a perfectly horizontal velocity of 9.7 m/s from a height of 1.8 meters. How long will it take f
sergejj [24]

Answer:A student shoots a spitball with a perfectly horizontal velocity of 9.7 m/s from a height of 1.8 meters. How long will it take for the spitball to hit the ground?

(ignore air resistance) (include units and correct number of significant figures)

Explanation:La respuesta es porque esa es la respuesta, la respuesta al número es 9.7 1.8 Divide =53.888

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3 years ago
How efficient are the small and large scale solar-power systems used in individual homes and industrial settings? What is the en
Leviafan [203]

Answer:

\color{Blue}\huge\boxed{Answer}

<em>The potential environmental impacts associated with solar power—land use and habitat loss, water use, and the use of hazardous materials in manufacturing—can vary greatly depending on the technology, which includes two broad categories: photovoltaic (PV) solar cells or concentrating solar thermal plants (CSP).</em>

Explanation:

I just answer the second question

4 0
3 years ago
Which type of mixture could this illustration represent?
Oksanka [162]

Answer:

A homogeneous mixture

Explanation:

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