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Simora [160]
2 years ago
15

Which of the following best explains why energy transfers are never 100%

Physics
2 answers:
xz_007 [3.2K]2 years ago
6 0

Answer:

A. Some energy is always converted to unusable forms in the

Explanation:

The second law relates to the quality of energy. This law states that whenever energy is transformed, some of must be degraded into a less useful form. In ecosystems, the biggest losses occur as respiration. 

hope it helps you and give me a brainliest

Kryger [21]2 years ago
6 0
I believe it’s A

Hope this helps
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How is it possible for two objects to have the same momentum but different velocities give an example
castortr0y [4]
Momentum is
p = mv, where m is the mass and v is the speed.
So, if two objects have the same momentum but different speeds, the must have different masses as well.
v1/v2 = m2/m1
The example is a car and a truck. Car has the mass 1000 kg and velocity 100 m/s, and truck has the mass 5000 kg and velocity 20 m/s. Use the formula above to determine is it true that they have the same momentum:
(100 m/s) / (20 m/s) = (5000 kg) / (1000 kg)
5 = 5
So, the example is correct.
Hope this helps! Good luck!
4 0
3 years ago
/Q: DHSMV definition/ i have to write 20 characters for whatever reason lol
cluponka [151]

<span><span>Department of Highway Safety and Motor Vehicles          OR</span></span>

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6 0
4 years ago
Resultant Displacement. I WILL GIVE BRAINLIEST!!!!
aleksley [76]

Answer:

displacement will be 83km from the marker that reads 249km.

8 0
3 years ago
How much heat must be removed from 200 pounds of blanched vegetables at 189 degrees F to freeze them to a temperature of 22 degr
Virty [35]

To solve this problem it is necessary to apply the concepts related to heat exchange in the vegetable and water.

By definition the exchange of heat is given by

Q =mc\Delta T

where,

m = mass

c = specific heat

\Delta T = Change in temperature

Therefore the total heat exchange is given as

\Delta Q = Q_w+Q_v

\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)

Our values are given as,

Total mass is M_T = 200lb ,however the mass of solid vegetable and water is given as,

m_v= 0.4*200lb = 80lb

m_w=0.6*200lb=120lb

T_i = 183\°F\\T_f = 22\°F\\c_w = 1Btu/lbF\\c_v = 0.24Btu/lbF

Replacing at our equation we have,

\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)

\Delta Q = (120)(1)(183-22)+(80)(0.24)(183-22)

\Delta Q = 22411.2Btu

Therefore the heat removed is 22411.2 Btu

6 0
3 years ago
0.8<br> How do convert this into a fraction
Umnica [9.8K]

Answer:

8/10 or 4/5

Explanation:

0.8 out of 1.0

4 0
4 years ago
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