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Aloiza [94]
3 years ago
14

If you change the mass of a moving object, you change its _______.

Physics
2 answers:
Paul [167]3 years ago
6 0
Momentum and inertia, Momentum=P. P=MV. M=mass and V=velocity. Mass is related to inertia so inertia=F. F=MA. A=acceleration.
Levart [38]3 years ago
4 0

Answer:

momentum

Explanation:

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Which of the following best defines insulator?
aliya0001 [1]

Answer:

A substance with low ability or no ability to conduct energy.

Such as Rubber,Silicone,Plastic

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4 years ago
Please help I need this fast
Ghella [55]
The solution has reacted.
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3 years ago
The resistance is 5 Ω and the amount of electric current is 2 A. This means that the amount of voltage is
Hatshy [7]

Answer:

I=2A

R=5

Explanation:

formula

V=IR

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Voltage=10 volt

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

3 0
3 years ago
A 5.50 kg sled is initially at rest on a frictionless horizontal road. The sled is pulled a distance of 3.20 m by a force of 25.
kiruha [24]

(a) 69.3 J

The work done by the applied force is given by:

W=Fd cos \theta

where:

F = 25.0 N is the magnitude of the applied force

d = 3.20 m is the displacement of the sled

\theta=30^{\circ} is the angle between the direction of the force and the displacement of the sled

Substituting numbers into the formula, we find

W=(25.0 N)(3.20 m)(cos 30^{\circ})=69.3 J

(b) 0

The problem says that the surface is frictionless: this means that no friction is acting on the sled, therefore the energy dissipated by friction must be zero.

(c) 69.3 J

According to the work-energy theorem, the work done by the applied force is equal to the change in kinetic energy of the sled:

\Delta K = W

where

\Delta K is the change in kinetic energy

W is the work done

Since we already calculated W in part (a):

W = 69.3 J

We therefore know that the change in kinetic energy of the sled is equal to this value:

\Delta K=69.3 J

(d) 4.9 m/s

The change in kinetic energy of the sled can be rewritten as:

\Delta K=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2 (1)

where

Kf is the final kinetic energy

Ki is the initial kinetic energy

m = 5.50 kg is the mass of the sled

u = 0 is the initial speed of the sled

v = ? is the final speed of the sled

We can calculate the variation of kinetic energy of the sled, \Delta K, after it has travelled for d=3 m. Using the work-energy theorem again, we find

\Delta K= W = Fd cos \theta =(25.0 N)(3.0 m)(cos 30^{\circ})=65.0 J

And substituting into (1) and re-arrangin the equation, we find

v=\sqrt{\frac{2 \Delta K}{m}}=\sqrt{\frac{2(65.0 J)}{5.50 kg}}=4.9 m/s

6 0
4 years ago
What is the total current for the circuit? (must include unit - A) I WILL GIVE BRAINLIEST!
Iteru [2.4K]

Answer:2 amperes

Explanation:

Voltage=120v

Total resistance=15+15+30

Total resistance=60 ohms

Current=voltage ➗ resistance

Current=120 ➗ 60

Current=2 amperes

3 0
3 years ago
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