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Aloiza [94]
3 years ago
14

If you change the mass of a moving object, you change its _______.

Physics
2 answers:
Paul [167]3 years ago
6 0
Momentum and inertia, Momentum=P. P=MV. M=mass and V=velocity. Mass is related to inertia so inertia=F. F=MA. A=acceleration.
Levart [38]3 years ago
4 0

Answer:

momentum

Explanation:

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A cyclist intends to cycle up a 7.70o hill whose vertical height is 126m. Assuming the mass of bicycle plus person is 75.0kg, ca
Ksivusya [100]

Answer:

92704.5 J

596.44737 N

Explanation:

m = Mass of person + bicycle = 75 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Vertical height = 126 m

\theta = Angle = 7.7°

d = Diameter = 0.388 m

Work done against gravity is given by

P=mgh\\\Rightarrow P=75\times 9.81\times 126\\\Rightarrow P=92704.5\ J

Work done is 92704.5 J

Force required is given by

F=\dfrac{mgrsin\theta}{\pi d}\\\Rightarrow F=\dfrac{75\times 9.81\times sin7.7\times 5.12}{\pi\times 0.388}\\\Rightarrow F=596.44737\ N

The force is 596.44737 N

7 0
2 years ago
Physics question A spacecraft descends vertically near the surface of Planet X. An upward thrust of 25.0kN from its engines slow
Evgesh-ka [11]
 F=m*a and m is constant on any planet 
25000-m*g=m*1.2 
10000-m*g=-m*0.80 
m*g is the weight 
25000/1.2-m*g/1.2=m 
10000/0.80-m*g/0.80=-25000/1.2+m*g/1.2 solve for m*g 
m*g=(10000/0.80+25000/1.2)/ (1/1.2+1/0.80) 
16 kN 
4 0
3 years ago
A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
shtirl [24]
In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂

The final mass of the trains will be:
10,000 + 10,000 = 20,000 kg
Substituting the values into the equation:

10,000 * 3 = 20,000 * v
v = 1.5 m/s

The final velocity of the trains will be 1.5 m/s
3 0
3 years ago
A 230-km-long high-voltage transmission line 2.0 cm in diameter carries a steady current of 1,100 A. If the conductor is copper
Molodets [167]

Answer:

28.23 years

Explanation:

I = 1100 A

L = 230 km = 230, 000 m

diameter = 2 cm

radius, r = 1 cm = 0.01 m

Area, A = 3.14 x 0.01 x 0.01 = 3.14 x 10^-4 m^2

n = 8.5 x 10^28 per cubic metre

Use the relation

I = n e A vd

vd = I / n e A

vd = 1100 / (8.5 x 10^28 x 1.6 x 10^-19 x 3.14 x 10^-4)

vd = 2.58 x 10^-4 m/s

Let time taken is t.

Distance = velocity x time

t = distance / velocity = L / vd

t = 230000 / (2.58 x 10^-4) = 8.91 x 10^8 second

t = 28.23 years

5 0
3 years ago
Read 2 more answers
light of a wavelength 600 nm shines on a soap bubble film. For what soap film thickness will destructive interference occur
VashaNatasha [74]

Answer:

The minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.

Explanation:

Given;

wavelength of light, λ = 600 nm

The minimum thickness of the soap bubble for destructive interference to occur is given by;

t = \frac{\lambda/n}{2}\\\\t = \frac{\lambda}{2n}

where;

n is refractive index of soap film = 1.33

t = \frac{\lambda}{2n} \\\\t = \frac{600*10^{-9}}{2(1.33)}\\\\t = 2.2556 *10^{-7} \ m\\\\t =  225.56 *10^{-9} \ m\\\\t = 225.56 \ nm

Therefore, the minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.

4 0
3 years ago
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