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frozen [14]
3 years ago
12

Can anyone help? Please and thank you

Physics
1 answer:
Juliette [100K]3 years ago
7 0

Kinetic energy is calculated as such: KE=\frac{1}{2} mv^{2} | therefore, KE=0.913598 J

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A constant force of 12N is applied for 3.0s to a body initially at rest. The final velocity of the body is 6.0ms–1. What is the
sp2606 [1]
From the question,
u = 0m {s}^{ - 1}
v = 6m {s}^{ - 1}

t = 3s
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Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.

Ft =m(v-u)


12(3.0)=m(6.0- \: 0)
This implies that

36.0 = 6m
m =  \frac{36.0}{6.0}
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You can also use the equation of linear motion,
v = u + at
6 = 0 + a(3)
6 = 3a
a =  \frac{6}{3}

a = 2 {ms}^{ - 2}
But
F=ma
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4 0
3 years ago
WILL GIVE BRAINLIEST!!!
Annette [7]

Answer:

Explanation:

Divergent Boundary

7 0
4 years ago
Read 2 more answers
If a spring has a spring constant of 5 N/m and it is stretched 20 cm, what is the force of the Spring
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Answer:

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Explanation:

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