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frozen [14]
3 years ago
12

Can anyone help? Please and thank you

Physics
1 answer:
Juliette [100K]3 years ago
7 0

Kinetic energy is calculated as such: KE=\frac{1}{2} mv^{2} | therefore, KE=0.913598 J

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How are dwarf planets different from true planets?
morpeh [17]

Answer:

The only difference between a planet and a dwarf planet is the area surrounding each celestial body. A dwarf planet has not cleared the area around its orbit, while a planet has.

Explanation:

the three criteria of the IAU for a full-sized planet are: It is in orbit around the Sun. It has sufficient mass to assume hydrostatic equilibrium (a nearly round shape). It has "cleared the neighborhood" around its orbit .

3 0
2 years ago
A football player who weighs 550 N stands indoors wearing her football boots. The boot’s
EleoNora [17]

Answer:

183333 Pa

Explanation:

The weight of the football player is : 550 N ,thus the force the player exerts on the floor is 550 N

The area of blades in contact with the floor is = 30cm² = 0.003 m²

Pressure = Force / Area

Pressure = 550 / 0.003

Pressure = 183333 Pa

3 0
2 years ago
an object is acted on by a drag force with a magnitude that is proportional to the speed. the object accelerates downward at 3.0
Nutka1998 [239]

The terminal speed of the object falling down is 66.67 m/s.

The terminal speed acquired by the body when,

Weight of the body = Drag force of the body

It is given,

Drag force is directly proportional to the speed,

So,

F = CV

Where F is drag force,

V is the speed,

C is the constant,

So, it can be written as C = F/V.

The weight of the body = mg

The weight of the body = 10m

M is the mass and g is the acceleration due to gravity,

The drag force when the speed is 20m/s.

Drag force = ma

a is the acceleration during the drag force which is given to be 3m/s²,

Drag force = 3m

Now we can write,

F₁/V₁ = F₂/V₂

F₁ is the drag force at 20m/s speed.

F₂ is the weight of the body and V₂ is the terminal speed,

Now, it can be written,

3m/20 = 10m/V₂

V₂ = 66.67 m/s.

So, the terminal speed is 66.67m/s.

To know more about terminal speed, visit,

brainly.com/question/14605362

#SPJ4

7 0
1 year ago
With what magnitude of force does a ball of mass 0.75 kilograms need to be hit so that it accelerates at the rate of 25 meters/s
serious [3.7K]

     Force = (mass) x (acceleration)

               = (0.75 kg) x (25 m/s²)

               =  (0.75 x 25)  kg-m/s²

               =    18.75 newtons .

Note that even though we're talking about a 'hit', the acceleration only
lasts as long as the bat is in contact with the ball.  Once the ball leaves
the bat, it travels at whatever speed it had at the instant when they parted. 
Any change in its speed or direction after that is the result of gravity, air
resistance, and the fielder's mitt.  I learned a lot about these things a few
weeks ago, since I live in Chicago, about 6 miles from Wrigley Field, in
a house full of Cubs fans.
8 0
3 years ago
Read 2 more answers
Can you answer my questions. Please help me ​
earnstyle [38]

Answer:

answered it.................

8 0
3 years ago
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