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RUDIKE [14]
2 years ago
6

Which expression is equivalent to the following complex fraction? StartFraction 2 Over x EndFraction minus StartFraction 4 Over

y EndFraction divided by StartFraction negative 5 Over y EndFraction + StartFraction 3 Over x EndFraction StartFraction 3 y + 5 x Over 2 (y minus 2 x) EndFraction StartFraction 2 (y minus 2 x) Over 3 y minus 5 x EndFraction StartFraction 2 (y minus 2 x) (3 y minus 5 x) Over x squared y squared EndFraction StartFraction x squared y squared Over 2 (y minus 2 x) (3 y minus 5 x) EndFraction
Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
4 0

The equivalent expression of \frac{\frac 2x - \frac 4y}{-\frac 5y + \frac 3x} is \frac {2(y - 2x)}{ 3y-5x}

<h3>How to determine the equivalent expression?</h3>

The complete question is in the attached image

We have:

\frac{\frac 2x - \frac 4y}{-\frac 5y + \frac 3x}

Take the LCM

\frac{\frac {2y - 4x}{xy}}{\frac{-5x + 3y}{xy}}

Divide through by xy

\frac {2y - 4x}{-5x + 3y}

Rewrite as:

\frac {2y - 4x}{ 3y-5x}

Factor out 2

\frac {2(y - 2x)}{ 3y-5x}

Hence, the equivalent expression of \frac{\frac 2x - \frac 4y}{-\frac 5y + \frac 3x} is \frac {2(y - 2x)}{ 3y-5x}

Read more about equivalent expression at:

brainly.com/question/24734894

#SPJ1

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Pepsi [2]
Hey there!
Let's first find an easier situation.
If we're saying:
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We're doing 10 divided by 5, because we're seeing how many 5's go into 10.
It's no different here.
We will be doing 6 divided by 3/4, just as we did with our simpler situation.
Using our "keep, switch, flip" rule (keep first term, change to multiplication, take reciprocal of second term)
we get:
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Hope this helps!
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So for example here, 6 · 1 is equal to 6 and 1 · 6 also equals 6.

Since 6 = 6, we can easily see that 6 · 1 must be equal to 1 · 6.

In more general terms, the commutative property of multiplication can be written as a · b = b · a where <em>a</em> and <em>b</em> are variables that can represent any numbers.

5 0
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So put the x as the dom and 6 as the num?
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