Answer:
$17.90 rounded up to 2dp
Step-by-step explanation:
11 = 60%
19 = 25%
16 = 15%
Total 3 hrs = $46 where average is 46/3 = 15.33 when same percentage of hours. For 10% higher which is 25% we take 19 x 0.10 = 1.533 and subtract = $17.47 for 25% - 40% of time in employment, but for 50% we find the average taking 11 x 0.45 = 6.8985 and add = $ 11 + 6.8985 = 17.8985 = $17.90
Answer:
The technician can combine 10 liters of pure acid with 30 liters of 20% acid to get the desired concentration
Step-by-step explanation:
For pure acid, the concentration will be 100%
Let the liters of pure be a and the liters of 20% be b
Since we want 40 liters of total;
a + b = 40 ••••••••(i)
Also,
100% of a + 20% of b = 40% of 40
a + 0.2b = 16 •••••(ii)
From ii , a = 16-0.2b
Put this into i
16-0.2b + b = 40
0.8b = 40-16
0.8b = 24
b = 24/0.8
b = 30
Since a + b = 40
a = 40 - b
a = 40-30
a = 10
H = m/y + z/y - d
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v
Answer:
D) 7 meters
Step-by-step explanation:
So I would start this off by plugging in the variables into side B. So if we were to plug 7 into B there would be 22 meters left of the perimeter. Therefore meaning 22 between A and C. Now A is 3 meters shorter than TWICE of B. So 7 times 2 is 14 and 14 minus 3 is 11. now we have 11 and 7 which equals 18. 29 minus 18 giving us 11 left. 11 is C. Now it says c is 4 meters longer than B so it 7 plus 4 is 11. And everything adds up. HOPE THIS HELPS.
let numerator be x and denominator be y
x = y-3...eqn 1
{(x +7)/ (y+5) } - x/y = 1/2... eqn 2
expandin eqn 2...
2y(x+7) - 2x(y+5) = y(y+5)
=》 2xy + 14y - 2xy -10x = y^2 + 5y
=》 14y - 10x = y^2 + 5y...eqn 3
subst x = y-3 in eqn 3
=》 y^2 + 5y - 14y + 10y -30 = 0
=》 y^2 + y - 30 = 0
solving the eqn
y = 5 thus x = 2
subst y = x+3 into eqn 2
2x +14 = x +8
x = -6