Answer:
Magnitude of electric field = E = q/Aε0
Explanation:
Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:
q = CV
And
V = q/C ……. (i)
The capacitance is given by the following equation:
C = Aε0/d ……. (ii)
Put equation (ii) in (i)
,
V = qd/ Aε0 …..(iii)
The electric field is defined as:
E = V/d …… (iv)
Put equation (iii) in (iv),
E = qd/ Aε0d
E = q/Aε0
Hence, the magnitude of electric field will be q/Aε0 .
<u>Frequency is the number of waves that passes at a given point every second.</u> The lower the frequency, the less waves there are. The higher the frequency, the more waves. <u>A wavelength is the distance between two frequency waves. </u>The higher the frequency, the less distance from two waves. The lower the frequency, the longer distance from two waves.
It would be 3.15 in meters
Penetrating electromagnetic radiation of a kind arising from the radioactive decay of atomic nuclei Answer:
Explanation: