All categories

2 years ago

Nkkljihghjhytuyftghvnvmjkhjkhjkh

Chemistry

1 answer:

NeX [460]2 years ago

4 0

Answer:

seriously ....,........

I don't like chemistry

You might be interested in

Determine two complex numbers, (a+bi) and (c+di), where a and d are irrational numbers and b and c are rational number

Dafna11 [192]

Answer:

The two complex numbers are $\sqrt2 + 5i \text{ and } 6 + \sqrt5i$

Explanation:

We have to form two complex numbers of the form

$a + ib\\c + id$

such that and d are irrational numbers and b and c are rational numbers.

We know that $\sqrt2, \sqrt3$ are irrational numbers.

5 and 6 are rational numbers.

We put

$a = \sqrt2\\b = 5\\c = 6\\d = \sqrt5\\a+ib = \sqrt2 + 5i\\c + id = 6 + \sqrt5i$

Thus, the two complex numbers are: $\sqrt2 + 5i \text{ and } 6 + \sqrt5i$

7 0

2 years ago

Read 2 more answers

One solution has a formula C (n) H (2n) O (n) If this material weighs 288 grams, dissolves in weight 90 grams, the solution will

saw5 [17]

Explanation:

The given data is as follows.

Boiling point of water ( $T^{o}_{b}) = 100^{o}C$ = (100 + 273) K = 323 K,

Boiling point of solution ( $T_{b}) = 101.24^{o}C$ = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

$\Delta T_{b} = (T_{b} - T^{o}_{b})$

= 374.24 K - 323 K

= 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

Let molar mass of the solute is x grams.

Therefore, Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

m = $\frac{288 g \times 1000}{x g \times 90}$

= $\frac{3200}{x}$

As, $\Delta T_{b} = k_{b} \times molality$

$1.24 = 0.512 ^{o}C/m \times \frac{3200}{x}$

x = $\frac{0.512 ^{o}C/m \times 3200}{1.24}$

= 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is $C_{n}H_{2n}O_{n}$ .

As, its empirical formula is $CH_{2}O$ and mass is 30 g/mol. Hence, calculate the value of n as follows.

n = $\frac{\text{Molecular mass}}{\text{Empirical mass}}$

= $\frac{1321.29 g}{30 g/mol}$

= 44 mol

Thus, we can conclude that the formula of given material is $C_{44}H_{88}O_{44}$ .

4 0

3 years ago

Find the number of moles of argon in 364 grams of argon.

serg [7]

Answer:D. 9.1 mole Ar

Explanation:

364 g Ar x 1 mole Ar / 40 g Ar

= 9.1 moles Ar

3 0

3 years ago

What does the atomic number represent?

saw5 [17]

C. The number of protons in the atoms nucleus.

3 0

3 years ago

Read 2 more answers

A car accelerates from rest to a speed of 24 m/s in 8 seconds. What is the car's average acceleration

densk [106]

Answer:

3 m/s

Explanation:

24 m/s over 8 seconds would be 24/8 making it be 3 m/s avg

4 0

2 years ago