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SashulF [63]
2 years ago
14

4 (JAMB) The diagram below shows a light see-saw, which is balanced horizontally by the weights W₁, W2, W3, W4 in the positions

shown: d a W₁ Fig. 4.44 W₂ b W3 WA Which of the following equations correctly represents the principle of the lever balance? A W₁ + W₂ = W3 + W4 B W₁-W₁ = W4 - W3 C W₁a+W₂b = W3c+Wad D (W₂-W₁)a= (W4 - W3)c E (W₁ + W₂ )ab = (W3+ W4)cd (SCIGCE) 4 ( JAMB ) The diagram below shows a light see - saw , which is balanced horizontally by the weights W₁ , W2 , W3 , W4 in the positions shown : d a W₁ Fig . 4.44 W₂ b W3 WA Which of the following equations correctly represents the principle of the lever balance ? A W₁ + W₂ = W3 + W4 B W₁ - W₁ = W4 - W3 C W₁a + W₂b = W3c + Wad D ( W₂ - W₁ ) a = ( W4 - W3 ) c E ( W₁ + W₂ ) ab = ( W3 + W4 ) cd ( SCIGCE )​
Physics
1 answer:
damaskus [11]2 years ago
6 0

The equation that represents the principle of the lever balance is:

  • W₁ + W₂ = W3 + W4; option A.

<h3>What is the principle of moments?</h3>

The principle of moments states when a body is in equilibrium, the sum of the clockwise moment about a point equals the sum of anticlockwise moment about that point.

A see-saw represents a balanced system of moments.

The sum of clockwise moment = The sum of anticlockwise moments.

Assuming W1 and W2 are clockwise moments and W3 and W4 are anticlockwise moments.

The equation will b:  W₁ + W₂ = W3 + W4

In conclusion, a balanced see-saw illustrates the principle of the lever balance.

Learn more about principle of moments at: brainly.com/question/20519177

#SPJ1

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Multiply the following three numbers and report your answer to the correct number of significant figures: 0.020cm x 50cm x 11.1c
Neko [114]

Answer:11.1

Explanation:

Three significant figures

5 0
3 years ago
Voltage needed to raise current to 3.75a using 20,20,200 resistor set
Varvara68 [4.7K]

<u>Answer:</u> The voltage needed is 35.7 V

<u>Explanation:</u>

Assuming that the resistors are arranged in parallel combination.

For the resistors arranged in parallel combination:

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

We are given:

R_1=20\Omega\\R_2=20\Omega\\R_3=200\Omega

Using above equation, we get:

\frac{1}{R}=\frac{1}{20}+\frac{1}{20}+\frac{1}{200}\\\\\frac{1}{R}=\frac{10+10+1}{200}\\\\R=\frac{200}{21}=9.52\Omega

Calculating the voltage by using Ohm's law:

V=IR         .....(1)

where,

V = voltage applied

I = Current = 3.75 A

R = Resistance = 9.52\Omega

Putting values in equation 1, we get:

V=3.75\times 9.52\\\\V=35.7V

Hence, the voltage needed is 35.7 V

7 0
3 years ago
Read 2 more answers
A grandfather clock has a pendulum that consists of a thin brass disk of radius r = 13.62 cm and mass 1.199 kg that is attached
Feliz [49]

Answer:

Explanation:

Expression for time period of a pendulum is as follows

T = 2\pi\sqrt{\frac{l}{g} }

l is length of pendulum from centre of bob and g is acceleration due to gravity

Given

Time period T = 1.583

g = 9.846

Substituting the values

1.583 = 2\pi\sqrt{\frac{l}{9.846} }

l = \frac{(1.583)^2\times9.846}{4\times(\frac{22}{7})^2 }

l = .6244 m

= 62.44 cm

Length of rod  = length of pendulum - radius of bob

= 62.44 - 13.62

= 48.82 cm

= .488 m

8 0
3 years ago
The critical angle for a certain air-liquid surface is 47.7°. What is the index of refraction of the liquid? Round to the neares
KengaRu [80]

Answer:

The index of refraction of the liquid is 1.35.

Explanation:

It is given that,

Critical angle for a certain air-liquid surface, \theta_1=47.7^{\circ}

Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1

Using Snell's law for air liquid interface as :

n_1\ sin\theta_1=n_2\ sin(90)

n_1\ sin(47.7)=1

n_1=\dfrac{1}{sin(47.7)}

n_1=1.35

So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.

5 0
3 years ago
36. The top floor of a building is 20 m above the basement. Show that the water pressure in the basement is nearly 200 kPa great
blagie [28]

Explanation:

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=196000/1000=196kpa which is almost 200kpa

8 0
2 years ago
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