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Natasha_Volkova [10]
2 years ago
12

A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep enc

ounters an unbanked curve of radius 50 m. The Jeep follows the road from B to C traveling at a constant speed of 10 m/s while the direction of the Jeep changes from east to south. What is the magnitude of the frictional force between the tires and the road as the Jeep negotiates the curve from B to C?
Physics
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

3600N

Explanation:

F=m\frac{v^2}{r}

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A client with hypertension who weighs 72.4 kg is receiving an infusion of nitroprusside (Nipride) 50 mg in D5W 250 ml at 75 ml/h
Mkey [24]

To solve this problem it is necessary to simply apply the concepts related to cross-multiply and proportion between units.

Let's start first by relating the amount of dose needed to be supplied per hour, in other words,

The infusion of 250ml should be supplied at a rate of 75ml / hour, so what amount x of mg hour should be supplied with 50Mg.

\frac{x}{75ml/hour} \rightarrow \frac{50mg}{250ml}

x \rightarrow \frac{50mg*75ml/hour}{250ml}

x \rightarrow \frac{3750mg}{250hour}

x \rightarrow 15\frac{mg}{hour}

Converting to mcg units we know that 1mg is equal to 1000mcg and that 1 hour contains 60 min, therefore

x \rightarrow 15\frac{mg}{hour}

x \rightarrow 15\frac{mg}{hour}(\frac{1000mcg}{1mg})(\frac{1hour}{60min})

x \rightarrow 250mcg/min

The dose should be distributed per kilogram of the patient so if the patient weighs 72.4kg,

Dose = \frac{250mcg/min}{72.4kg}

Dose = 3.5 \frac{mcg/min}{kg}

Therefore the client will receive 3.5mcg/kg/min.

8 0
3 years ago
How many joules are required to heat .250 kg of liquid water from 0 °C to 100 °C ?
dedylja [7]

Answer:

Specific heat of water is 4.186 J/g/C. The heat required to raise the temperature by

is

Here  is mass of water being heated,  specific heat of water and  change in temperature.

Here .

Heat energy required is

Explanation:

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2 years ago
Carlita and Max were bowling after school. Carlita was getting frustrated because of the small number of pins she kept knocking
kotykmax [81]
Slide with her left foot. hope this is helpful
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How do you find the weight of an object when given the mass and acceleration?
murzikaleks [220]

Weight of an object is given by the formula W = m x g , where

m : mass of the object

g : gravitational acceleration

It is <u>independent of the horizontal </u><u>acceleration</u>.  

<h3>What do we mean by weight of an object?</h3>

Weight is a gauge of how strongly gravity is<u> pulling something down.</u> It is dependent on the object's mass, or how much matter it consists of. It also depends on the <u>object's uniformly distributed</u> downward acceleration caused by gravity.

This equation can be used to express weight:

 W = m x g

<h3>What is the difference between weight and mass of an object?</h3>

In everyday speech, the phrases "mass" and "weight" are frequently used interchangeably; nevertheless, the two concepts don't have the same meaning. In contrast to weight, which is a <u>measurement of</u> how the <u>force</u> of gravity works upon a mass, mass is the <u>amount of substance</u> in a material.

To learn more about gravity and acceleration :

brainly.com/question/13860566

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3 0
1 year ago
In noisy factory environments, it's possible to use a loudspeaker to cancel persistent low-frequency machine noise at the positi
Vaselesa [24]

Answer:

7.39 m or 3.61 m

Explanation:

\lambda = Wavelength

f = Frequency = 90 Hz

v = Speed of sound = 340 m/s

Path difference of the two waves is given by

s_1-s_2=\frac{\lambda}{2}

Velocity of wave

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{340}{90}\\\Rightarrow \lambda=3.78\ m

s_1=s_2\pm\frac{\lambda}{2}\\\Rightarrow s_1=5.5\pm \frac{3.78}{2}\\\Rightarrow s_1=7.39\ m, 3.61\ m

So, the location from the worker is 7.39 m or 3.61 m

7 0
3 years ago
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