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Natasha_Volkova [10]
2 years ago
12

A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep enc

ounters an unbanked curve of radius 50 m. The Jeep follows the road from B to C traveling at a constant speed of 10 m/s while the direction of the Jeep changes from east to south. What is the magnitude of the frictional force between the tires and the road as the Jeep negotiates the curve from B to C?
Physics
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

3600N

Explanation:

F=m\frac{v^2}{r}

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6 0
2 years ago
A car is traveling at 21m/s. It accelerates at 1.4m/s2 for 11s. How fast is the car moving after the acceleration?
nata0808 [166]

Answer:

v=u+at

v=21+1.4(11)

v=21+15.4

v=36.4

3 0
3 years ago
BRAINLEST FOR CORRECT ANSWER
xxMikexx [17]

Answer:

3kg sledgehammer swung at 1.5 m/s

Explanation:

Small Sledgehammer:

Mass:3.0

Velocity:1.5

MASS×VELOCITY=MOMENTUM

3.0×1.5= 4.5 (momentum)

Large Sledgehammer:

Mass:4.0

Velocity:0.9

4.0×0.9=3.6 (momentum)

higher momentum is the smaller Sledgehammer.

3 0
3 years ago
A cube of side 0.2 m rests on the floor as shown.
andrey2020 [161]
Pressure= hqg
H=depth
q=density
g=gravity

h=0.2
q=7
g=10

0.2*7*10= 14pa

FINAL ANSWER = 14pa
4 0
1 year ago
What is the net force on this object?​
Mariulka [41]
Answer=8N

Explantion:
20-20=0
22-14=8N
5 0
3 years ago
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