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saw5 [17]
3 years ago
8

A snail can move approximately.3 meters per minute. How many meters can a snail travel in 45min?

Physics
1 answer:
Aloiza [94]3 years ago
6 0

Answer:

13.5

Explanation:

.3×45=13.5 See that is correct u can check with a calculator, I used a calculator

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Using the periodic table, predict the formulas of stable ionic compounds. Select THREE that are correct.
AleksandrR [38]
The first one,second one and the forth one are correct
6 0
3 years ago
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A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica
-BARSIC- [3]

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

7 0
3 years ago
∠1 and ∠2 are vertical angles. If m∠1 = (17x + 1)° and m∠2 = (20x – 14)°, find m∠2. Answer with "m∠2=_"
Bingel [31]

Answer:

m<2 = 86

Explanation:

Vertical angles means the angles are equal to each other so:

<1 = <2

17x + 1 = 20x - 14

17x - 20x = -14 - 1

-3x = -15

x = 5

m<2:

20x - 14

20(5) - 14

100 - 14

86

8 0
3 years ago
Define the term “force”.
Aleonysh [2.5K]

Energy that is applied to an object.

--TheOneandOnly003

3 0
3 years ago
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The drinking water needs of an office are met by cooling tab water in a refrigerated water fountain from 23 to 6°C at an average
Ratling [72]

Answer:

The correct option is;

(c) 64W

Explanation:

Here we have the Coefficient Of Performance, COP given by

COP = \frac{Q_{cold}}{W} = 3.1

The heat change from 23° to 6°C for a mass of 10 kg/h which is equivalent to 10/(60×60) kg/s or 2.78 g/s we have

Q_{cold} = m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J

Therefore, plugging in the value for  Q_{cold} in the COP equation we get;

COP = \frac{197.39 }{W} = 3.1 which gives

W =  \frac{197.39 }{3.1} = 63.674 \ J

Since we were working with mass flow rate then the power input is the same as the work done per second and the power input to the refrigerator = 63.674 J/s ≈ 64 W.

The power input to the refrigerator is approximately 64 W.

4 0
3 years ago
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