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arlik [135]
3 years ago
12

(Brainliest) How are radio waves used in cell phone wireless communication technology?

Physics
1 answer:
poizon [28]3 years ago
5 0

Radio waves are used in cell phone wireless communication by this: Radio waves are released from the cell phone and travel to satellites in the stratosphere. After they reach the satellite, they are redirected to the recipient of the call/text.

Hope this helps! Can I have brainliest please?

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What happens when you modify a pwc's exhaust system?
Rasek [7]
PWC stands for Personal WaterCraft.
When you modify a PWC's exhaust system it may raise noise to an illegal level.
<span>That's why, you should avoid maneuvers that cause the engine exhaust to lift out of the water. </span>The noise can be irritant to people, so avoid making excessive noise near residential and camping areas.
4 0
2 years ago
Carbon-14 has a half-life of 5,700 years. How long will it take for 6.25% of the Carbon-14 to be remaining?
kupik [55]

Half life is 5700 years,that is 50%.

6.25% means 1/16 of the life is left.

T^1/16 =T^1/2*4.

5700 × 4 =22800 years

7 0
2 years ago
A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.
Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V  = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length  n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

8 0
3 years ago
What kind of radiation is stopped by a piece of paper
Zina [86]
Three types of radioation - Alpha, Beta, Gamma. hope this helps
4 0
2 years ago
Read 2 more answers
An 81.5-kg man stands on a horizontal surface.
OLga [1]

Answer:

a)V= 0.0827 m³

b)P=181.11 x 10²  N/m²

Explanation:

Given that

m = 81.5 kg

Density ,ρ = 985 kg/m³

As we know that

Mass = Volume x Density

81.5 = V x 985

V= 0.0827 m³

The force exerted by weight = m g

 F= m g= 81.5 x 10 = 815 N      ( Take ,g= 10 m/s²)

Area ,A= 4.5 x 10⁻² m²

The Pressure P

P=\dfrac{F}{A}

P = \dfrac{815}{4.5\times 10^{-2}}\ N/m^2

P=181.11 x 10²  N/m²

7 0
3 years ago
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