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KIM [24]
2 years ago
8

PLEASE HELP!! 50 points. The answer is not 2.6 m/s.

Physics
1 answer:
Drupady [299]2 years ago
3 0

Answer:

A

Explanation:

5.2mm/s

hope this helps

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PLEASE HELP! A river current has a velocity of 5km/h relative to the shore, and a boat moves in the same direction as the curren
Usimov [2.4K]

add the river's velocity to the boat's velocity

5+ 5 = 10 km/h

Hope this helps!

5 0
4 years ago
What is the weight of a 20kg stone?​
worty [1.4K]

Answer: w = 200N

Explanation:

w = mg

m = 20kg

g = 10m/s^ (approximately)

w = 20kg . 10m/s^

w = 200N

5 0
3 years ago
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Which characteristics describe a point charge?
wolverine [178]

Answer:

C

Explanation:

becauase i just tooke the test

6 0
3 years ago
The current in a wire is 4.00A. How much time is needed for 1 mole of electrons (6.02×1023 electrons) to pass a point in the wir
scZoUnD [109]

Answer:

t= 24080 s

Explanation:

Given that

Current in the wire ,I = 4 A

The charge ,q = 6.02 x 10²³ e C

We know that

I=\dfrac{q}{t}

I=Current  

q=Charge

t=time

t=\dfrac{q}{I}

Now by putting the values in the above equation we get'

t=\dfrac{6.02\times 10^{23}\times 1.6\times 10^{-19}}{4}\ s

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8 0
3 years ago
What height will the object reach? 12 points. Will give brainliest.
umka21 [38]

Answer:

12.7 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 56.7 Km/hr

Maximum height (h) =..?

First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:

Initial velocity (m/s) = 56.7 x 1000/3600

Initial velocity (m/s) = 15.75 m/s

Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:

Initial velocity (u) = 15.75 m/s

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

v = u – gt (since the ball is going against gravity)

0 = 15.75 – 9.8 × t

Rearrange

9.8 × t = 15.75

Divide both side by 9.8

t = 15.75/9.8

t = 1.61 secs.

Finally, we shall determine the maximum height as follow

h = ½gt²

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.61 secs.

Height (h) =..?

h = ½gt²

h = ½ × 9.8 × 1.61²

h = 4.9 x 1.61²

h = 12.7 m

Therefore, the maximum height reached by the ball is 12.7 m

3 0
3 years ago
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