Ask question

Ask question

All categories

3 years ago

14

Objects want to keep doing the same thing is a way of stating ....

2 answers:

ivolga24 [154]3 years ago

5 0

Answer:

Objects want to keep doing the same thing is a way of stating Newtons first law.

galben [10]3 years ago

3 0

Answer:

Objects want to keep doing the same thing is a way of stating Newtons First Law.

You might be interested in

What girl plays on xbox 14+

elena-s [515]

Answer:

This kinda sus

Explanation:

maybe not on brainly?

8 0

3 years ago

Read 2 more answers

Why do planets rings surround them and not the sun

Shalnov [3]

Well, the rings surrounding a planet are made out of rock. A ring surrounding the sun would be impossible since the sun can reach more than 27 million degrees Fahrenheit (15 million degrees Celsius.)

Hope this helped.

7 0

4 years ago

A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration

Rufina [12.5K]

To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

$F_f = \mu N$

Where,

$\mu =$ Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

$m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\$

By condition of Balance the friction force must be equal to the total net force, that is to say

$F_{net} = F_f$

$m_{total}a = \mu m_hg$

$(m_h+m_c)a = \mu*m_h*g$

Re-arrange to find acceleration,

$a= \frac{\mu*m_h*g}{(m_h+m_c)}$

$a = \frac{0.894*242*9.8}{(242+224)}$

$a = 4.54 m/s^2$

Therefore the acceleration the horse can give is $4.54m/s^2$

3 0

3 years ago

Research shows that Mount Everest Grows an Average of 4 millimeters each year. How many will it take to grow 720 millimeters.?

maria [59]

Time = 720 / 4 =180years

7 0

3 years ago

Read 2 more answers

Would a measured force of (46.5 0.8 N  ) be in agreement with a theoretically calculated force of (48.4 0.6 N  ) ? Show your w

OverLord2011 [107]

Answer:

A measured force of (46.5 0.8 N  ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N  )

Explanation:

From the question we are told that

Measured force is $F_M = [46.5 \pm 0.8 \ N ]$

Calculated force is $F_c = [48.4 \pm 0.6 \ N ]$

Generally the measured force in interval form is

$46.5 - 0.8 < F_M < 46.5 + 0.8$

=> $45.7 < F_M < 47.3$

Generally the calculated force in interval form is

$48.4 - 0.6 < F_c < 48.4 + 0.6$

=> $47.8 < F_M$

Generally looking both interval we see that they do not intersect at any point Hence

A measured force of (46.5 0.8 N  ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N  )

8 0

3 years ago