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2 years ago

9

Two examples of hydraulic brake

1 answer:

rjkz [21]2 years ago

3 0

Answer:

1). Brake pedal or lever

2). A pushrod also called an actuating rod

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sukhopar [10]

I believe the answer is true.

3 0

3 years ago

Read 2 more answers

If a calibration curve of absorbance vs procaine hydrochloride concentration (mol L') is linear with the equation y = 240000x fo

coldgirl [10]

Answer:

8000 L/ mol cm is the value of the molar absorptivity coefficient.

Explanation:

The slope of the absorbance- concentration graph is equal to the product of path length and molar absorptivity coefficient.

$\frac{dA}{dc}=\epsilon l$

$\frac{dA}{dc}$ = Rate of change of absorbance with respect to concentration

$\epsilon$ = molar absorptivity coefficient

l = Path-length

Given the slope of graph of absorbance vs procaine hydrochloride concentration.

y = 240000 x (linear equation)

Path length of cuvette = 3 cm

$A=240000 c$

$A=\epsilon c\times l=(\epsilon l)\times c$

$240000=\epsilon \times 3$

$\epsilon =\frac{24000}{3}=8000$

The units of $\epsilon = 8000 l/mol cm$

8000 L/ mol cm is the value of the molar absorptivity coefficient.

3 0

3 years ago

A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the

Tcecarenko [31]

Answer: $8.493(10)^{-3} m/s$

Explanation:

According to the conservation of linear momentum principle, the initial momentum $p_{i}$ (before the collision) must be equal to the final momentum $p_{f}$ (after the collision):

$p_{i}=p_{f}$ (1)

In addition, the initial momentum is:

$p_{i}=m_{1}V_{1}+m_{2}V_{2}$ (2)

Where:

$m_{1}=1.71(10)^{14} kg$ is the mass of the comet

$m_{2}=6.06(10)^{20} kg$ is the mass of the asteroid

$V_{1}=3.01(10)^{4} m/s$ is the velocity of the comet, which is positive

$V_{2}=0 m/s$ is the velocity of the asteroid, since it is at rest

And the final momentum is:

$p_{f}=(m_{1}+m_{2})V_{f}$ (3)

Where:

$V_{f}$ is the final velocity

Then :

$m_{1}V_{1}+m_{2}V_{2}=(m_{1}+m_{2})V_{f}$ (4)

Isolating $V_{f}$ :

$V_{f}=\frac{m_{1}V_{1}}{m_{1}+m_{2}}$ (5)

$V_{f}=\frac{(1.71(10)^{14} kg)(3.01(10)^{4} m/s)}{1.71(10)^{14} kg+6.06(10)^{20} kg}$

Finally:

$V_{f}=8.493(10)^{-3} m/s$ This is the final velocity, which is also in the positive direction.

8 0

3 years ago

Freddie drives his car 10 km North. He stops for gas and then drives 5 km South.

fgiga [73]

Answer:

5 km

Explanation:

displacement is the straight line distance from a particular point. since north and south are in opposite directions, it means that he has taken a u-turn

thus, 10 - 5 = 5km displacement

4 0

2 years ago

Distance v. Time

Allushta [10]

Answer:

4

(m)

2 ( s )

Explanation:

ok...........

3 0

3 years ago