Answer:
Magnitude of induced emf will be 87.5 volt
Direction of induced emf will be clockwise
Explanation:
We have given number of turns in the coil N = 50
Initial area
Time is given dt = 0.1 sec
Magnetic field B = 1.25 T
From Faraday's law of electromagnetic induction
n
So magnitude of induced emf is 87.5 volt
Direction of induced emf will be clockwise
(A)
The energy stored by the system is given by
where
P is the power provided
t is the time elapsed
In this case, we have
P = 60 kW = 60,000 W is the power
t = 7 is the time
Therefore, the energy stored by the system is
(B) 4830 rad/s
The rotational energy of the wheel is given by
(1)
where
is the moment of inertia
is the angular velocity
The moment of inertia of the wheel is
where M is the mass and R the radius of the wheel.
We also know that the energy provided is
So we can rearrange eq.(1) to find the angular velocity:
(C)
The centripetal acceleration of a point on the edge is given by
where
is the angular velocity
R = 0.12 m is the radius of the wheel
Substituting, we find
