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3 years ago

If a pebble is being transported in a stream by rolling, how does the velocity of it compare to the velocity of the stream?

1 answer:

3 0

Streams carry sediment, like pebbles, in their flows. The pebbles can be in a variety of locations in the flow, depending on it's size, the balance between the upwards velocity on the pebble (drag and lift forces), and it's settling velocity.

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A 4.55 nF parallel-plate capacitor contains 27.5 μJ of stored energy. By how many volts would you have to increase this potentia

aivan3 [116]

Answer:

$\Delta V=V_{2}-V_{1}=45.4V$

Explanation:

The energy, E, from a capacitor, with capacitance, C, and voltage V is:

$E=\frac{1}{2} CV^{2}$

$V=\sqrt{2E/C}$

If we increase the Voltage, the Energy increase also:

$V_{1}=\sqrt{2E_{1}/C}$

$V_{2}=\sqrt{2E_{2}/C}$

The voltage difference:

$V_{2}-V_{1}=\sqrt{2E_{2}/C}-\sqrt{2E_{1}/C}$

$V_{2}-V_{1}=\sqrt{2*55*10^{-6}/4.55*10^{-9}}-\sqrt{2*27.5*10^{-6}/4.55*10{-9}}=45.4V$

5 0

3 years ago

A wave with a frequency of 5Hz travels a distance of 40mm in 2 seconds.What is the speed of the wave

Sindrei [870]

Answer:

20mm per second

Explanation:

5 0

3 years ago

Two narrow, parallel slits separated by 0.850 mm are illuminated by 600-nm light, and the viewing screen is 2.80 m away from the

CaHeK987 [17]

Answer:

a) 7.947 radians

b) $\mathbf{\frac{I}{I_{max}}=0.4535}$

Explanation:

y = Distance from central bright fringe = 2.5 mm

λ = Wavelength = 600 nm

L = Distance between screen and source = 2.8 m

d = Slit distance = 0.85 mm

$tan\theta =\frac{y}{L}\\\Rightarrow tan\theta =\frac{2.5}{2800}=0.000892\\\Rightarrow \theta=tan^{-1}0.000892=0.05115^{\circ}$

$\Delta r= dsin\theta\Rightarrow \Delta r=dsin0.05115=7.589\times10^{-7}$

a) Phase difference

$\phi=\frac{2\pi}{\lambda}\Delta r\\\Rightarrow \phi=\frac{2\pi}{600\times 10^{-9}}7.589\times10^{-7}=7.947\ rad$

∴ Phase difference between the two interfering waves on a screen at a point 2.50 mm from the central bright fringe is 7.947 radians

b) $\frac{I}{I_{max}}=cos^2\frac{\phi}{2}\\\Rightarrow \frac{I}{I_{max}}=cos^2\frac{7.947}{2}\\\Rightarrow \mathbf{\frac{I}{I_{max}}=0.4535}$

∴ Ratio of the intensity at this point to the intensity at the center of a bright fringe $\mathbf{\frac{I}{I_{max}}=0.4535}$

8 0

3 years ago

Your brother is insisting that you’ll never hear a sound produced behind a barrier wall at the end of your yard you notice that

Tresset [83]

Answer

D.Diffraction

Explanation

Diffraction is a property that is experienced by waves when they come across a barrier when they are in motion.

The ways tends to curve behind the barrier. This is called diffraction of waves.

Now, sound is a wave and it also experience diffraction. . So the brother will be able to hear the sound due to diffraction

8 0

3 years ago

Read 2 more answers

The position of a circuit breaker (CB) are .............

AlexFokin [52]

A circuit breaker is an automatically operated electrical switch designed to protect an electrical circuit from damage caused by excess current from an overload or short circuit. Its basic function is to interrupt current flow after a fault is detected.

I hope that this answer helps you

6 0

3 years ago