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jok3333 [9.3K]
3 years ago
10

A piano string having a mass per unit length equal to 4.80 ✕ 10−3 kg/m is under a tension of 1,300 N. Find the speed with which

a wave travels on this string.
Physics
1 answer:
fredd [130]3 years ago
8 0

Answer:

Velocity of wave (V) = 5.2 × 10² m/s

Explanation:

Given:

Per unit length mass (U) = 4.80 × 10⁻³ kg/m

Tension (T)= 1,300 N

Find:

Velocity of wave (V)

Computation:

Velocity of wave (V) = √T / U

Velocity of wave (V) = √1300 / 4.80 × 10⁻³

Velocity of wave (V) = √ 270.84 × 10³

Velocity of wave (V) = 5.2 × 10² m/s

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What electrical force dies a Uranium nucleus exert on one of its inner electrons, located at a distance of 175 picometers (= 1.7
AlekseyPX

Answer:

correct option is d) 7.0 x 10^-7 N

Explanation:

given data

distance = 175 picometers = 1.75 × 10^{-10}  m

to find out

electrical force

solution

we know atomic no of uranium is 92

and charge on electron is = 1.6 × 10^{-19} C

and electrical force is express as

electrical force = \frac{1}{4 \pi \epsilon _o} \frac{q1q2}{r^2}    .............1

put here value we get

electrical force = 9*10^9 \frac{92*(1.6*10^{-19})^2}{(1.75*10^{-10})^2}

electrical force =  6.921 × 10^{-7} N

so correct option is d) 7.0 x 10^-7 N

5 0
3 years ago
Read 2 more answers
Which ground rule for group work was broken in the following scenario?
SpyIntel [72]

Answer:

йцу21241

Explanation:

ere taking their seats. Finn and Jan presented the progress they had made on the project since the last meeting. Everyone engaged in the subsequent discussions, asking questions and offering ideas.

5 0
2 years ago
Read 2 more answers
A man on a bicycle of total mass of 10kg has a Velocity of 2 ms.' He Paddles faster for 5 seconds and the velocity Increase to i
sesenic [268]

Answer:

the value of force, F=4.0N

Explanation:

Firstly, recall velocity-time equation

  • v=u+at
  • (4)=(2)+a(5)
  • a=0.4m/s²

Secondly, recall the Newton's 2nd Law

  • <em>F</em><em>=</em><em>ma</em>
  • <em>F</em><em>=</em><em>(</em><em>1</em><em>0</em><em>)</em><em>(</em><em>0</em><em>.</em><em>4</em><em>)</em>
  • <em>F</em><em>=</em><em>4</em><em>.</em><em>0</em><em>N</em>
7 0
1 year ago
A wire loop of radius 0.37 m lies so that an external magnetic field of magnitude 0.35 T is perpendicular to the loop. The field
Galina-37 [17]

Answer:

168.57 mV

Explanation:

Initial magnetic flux = BA , B magnetic field and A is area of loop

= .35 x 3.14 x .37²

= .15 Weber

Final magnetic flux

= - .2 x 3.14 x .37²

= -  .086 Weber

change in flux

.15 +  .086

= .236 Weber

rate of change of flux

= .236 / 1.4

= .16857 V

= 168.57 mV

5 0
3 years ago
Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 j electrical energy is
MAVERICK [17]

Here is the energy that is left after the quantity of energy is transformed: 750 j of electrical energy is changed into 400 j of kinetic or mechanical energy, which is then turned into 0.32 j of efficient energy.

To run the fan, electrical energy is utilized.

Here, under the specified circumstances, 750 J of electrical energy is utilized to operate the fan, which is transformed into 400 J of kinetic energy. As a result, 350 J of energy is wasted due to various frictional and resistive losses.

Therefore, we may conclude that only 400 J of the 750 J available energy is used to power the fan, with the remaining energy being wasted as a result of friction.

Additionally, we can state that this fan's effectiveness will be

n = Useful ÷ Total

n = 400 ÷ 750

n = 8 ÷ 25

n = 0.32

Learn more about energy at

brainly.com/question/15915007?referrer=searchResults

#SPJ4

4 0
11 months ago
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