Question

6 An infinite non-conducting sheet has a surface charge density o = 5.80pC/m². (a) How

Answer 1

a. Work done = 2. 0648 Joules

b. Electrical potential, V = 4. 03 × 10^10 volts

How to determine the parameters

a. Work done = force × distance

Force = density × acceleration due to gravity

Force = 5. 80 × 10

Force = 58 Newton

We have that distance = 3. 56cm = 0. 0356 m

Work done = 58 × 0. 0356

Work done = 2. 0648 Joules

b. The formula for electric potential is given thus,

Electric potential, V = $k\frac{q}{r}$

r = 0. 0356m

k = Coulomb's constant = $8.98*10^9$kg⋅m3⋅s−4⋅A−2.

q= 1.60x10^-¹C

substitute into the formula

Electric potential, V = $8. 98$ × $10^9$ × $\frac{1. 6 * 10^-^-1}{0. 0356}$

Electric potential, V = $8. 98 * 10^9$ × $4. 494$

Electric potential, V = $4. 03 * 10^1^0$ volts

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