The copper is a conductor and the rubber is an insulator. Conductors allow electricity to be transmitted freely while insulators prevent most of the current from transmitting. The outer electrons of the conductor's atoms are not very stable and are able to freely move around the material. In a material such as copper, the valence electrons are essentially free and strongly repel each other. The atoms of insulators such as rubber, hold tight to their outer electrons which prevents electricity from flowing freely through.
A.900 watts That would be your correct answer
Answer:
a) and c).
Explanation:
For a complete destructive interference occur, it must be met the following condition relating the wavelength, and the difference in the paths taken by the sound emitted by the sources until arriving to the listening point:
d = |dA- dB| = (2n-1)*(λ/2)
For n= 1, d = λ/2 = 0.25 m, it doesn't meet any of the cases.
For n=2, d= 3*(λ/2) = 0.75 m
In the case a) we have dA = 2.15 m and dB = 3.00 m, so dB-dA = 0.75 m, which means that in the location stated by case a) a complete destructive interference would occur.
For n=3, d= 5*(λ/2) = 5*0.25 m = 1.25 m.
This is just the case c) because we have dA = 3.75 m and dB = 2.50 m, so dA-dB = 1.25 m, which means that in the location stated by case c) a complete destructive interference would occur also.
The remaining cases don't meet the condition stated above, so the statements found to be true are a) and c),
Answer:
<em>n =1.33 revolutions</em>
Explanation:
<u>Uniform Circular Motion</u>
The angular speed can be calculated in two different ways:
Where:
v = tangential speed
r = radius of the circle described by the rotating object
Also:
Where:
f = frequency
Solving for f:
Since the frequency is calculated when the number of revolutions n and the time t are known:
We can solve for n:
n=f.t
The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:
Now we calculate f:
Calculating the number of revolutions:
n = 0.04421*30
n =1.33 revolutions
<span>your phenotype hope this helps :)</span>
