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Alekssandra [29.7K]
2 years ago
13

Triangles A B C and N M Q are shown. Sides B C and N M are congruent. Angles A B C and Q N M are congruent. Angles B C A and N M

Q are both right angles.
Nessa proved that these triangles are congruent using ASA. Roberto proved that they are congruent using AAS. Which statement and reason would be included in Roberto’s proof that was not included in Nessa’s proof?

Given: AngleB ≅ AngleN; BC ≅ NM; AngleC is right; AngleM is right
Prove: TriangleABC ≅ TriangleQNM

AngleA ≅ AngleQ because of the third angle theorem.
AB ≅ QN because they are both opposite a right angle.
BC ≅ NM because it is given.
AngleC ≅ AngleM because right angles are congruent.
Mathematics
1 answer:
Ugo [173]2 years ago
8 0

What would be included to prove both triangles are congruent by the AAS theorem is: B. AB ≅ QN because they are both opposite a right angle.

<h3>What is the AAS Congruence Theorem?</h3>

The AAS congruence theorem states that two triangle are congruent if both have two pairs of corresponding congruent angles and a pair of non-included corresponding congruent sides.

In the image given, since AB and QN both lie opposite a right triangle, then they are congruent to each other.

Therefore, to prove both triangles are congruent by AAS theorem, what would be included is: B. AB ≅ QN because they are both opposite a right angle.

Learn more about AAS congruence theorem on:

brainly.com/question/3168048

#SPJ1

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Could someone pls explain this step by step? Really simplify it pls because I don't understand it at all.
Lunna [17]

Answer:

  • y = 2x -6
  • y = -x +2
  • y = 4/5x -2
  • y = -3/2x +4

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx +b . . . . . where m is the slope, and b is the y-intercept

For these equations, writing them in slope-intercept form means "solve for y." You always do any "solve for ..." problem by undoing the operations that are done to the variable. Addition is undone by adding the opposite. Multiplication is undone by division.

As always, whatever operation we perform on one side of the equal sign must also be performed on the other side. That is how the equal sign remains valid.

__

<h3>a)</h3>

  1/2y = x -3

All we need to do is get rid of the coefficient of y. We can do that by dividing by 1/2, or multiplying by 2. The latter is easier to see, perhaps.

 2(1/2y) = 2(x -3)

  y = 2x +2(-3)

  y = 2x -6

__

<h3>b)</h3>

  x +y = 2

Here, we need to undo the addition of x. We do that by adding (-x) to both sides of the equation.

  -x +x +y = -x +2

  y = -x +2

__

<h3>c)</h3>

  4x -5y -10 = 0

This is a combination of the above operations. We can separate the y-term from the others by either subtracting the others, or adding the opposite of the y-term. We choose the latter, because that will give a positive coefficient for y. Adding 5y to both sides gives ...

  4x -5y +5y -10 = 5y

  5y = 4x -10 . . . . . . . . simplify and put y on the left

Now, we need to divide by the coefficient of y. We do that to both sides of the equation.

  5y/5 = (4x -10)/5

  y = 4/5x -10/5

  y = 4/5x -2

__

<h3>d)</h3>

  3x = -2y +8

We have a constant with the y-term. To get rid of it, we add its opposite to both sides.

  3x -8 = -2y +8 -8

  3x -8 = -2y

As before, we divide by the coefficient of y:

  (3x -8)/(-2) = (-2y)/(-2)

  -3/2x +4 = y

  y = -3/2x +4

3 0
2 years ago
Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0
3 years ago
A cone has a diameter of 8 units and a height of 8 units. units, and its volume is Its radius is volume of cubic units. If a sph
aev [14]

The above question is not complete because it was not written and arranged properly

Complete Question

1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.

2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.

3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder. Answer: 1) Volume of the cone = 134.04cubic units

2)Volume of the cylinder = 402.12cubic units

3) Volume of the sphere= 268.08 cubic units. Hence, if a sphere has the same radius as the cylinder, its volume is 2/3 times the volume of the cylinder.

Step-by-step explanation:

1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.

Volume of a cone = 1/3πr²h

h = 8 units

r = 4 units

Volume = 1/3 × π × 4² × 8

134.04cubic units

2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.

Volume of a cylinder = πr²h

Height and radius is the same as that of the cones hence,

h = 8 units

r = 4 units

= π × 4² × 8

= 402.12cubic units.

3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder.

Volume of a Sphere = 4/3πr³

r = radius of the cylinder = 4 units

Volume of a Sphere = 4/3 × π × 4³

= 268.08 cubic units.

From the above question, we are asked to compare the volume of the sphere with the volume of the cylinder

Volume of the sphere : Volume of the cylinder

268.08 cubic units : 402.12 cubic units

268.08/402.12 = 2/3

Therefore, the volume of the sphere is 2/3 times the volume of the cylinder

6 0
2 years ago
Mr.Fields ordered 3 tons of gravel for a drive way at a factory.how many pounds of gravel did he order?
soldi70 [24.7K]
Mr.Fields would have 6,000 pounds

4 0
4 years ago
PLZ HELP if you dont know just dont answer i will give brainliest if you answer right
marta [7]

Answer:  The answer for 1. is 216

The answer for 2. is 224

The answer for 3. is 90

The answer for 4. is 40

The answer for 5. should be 80

Step-by-step explanation:

6 0
3 years ago
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