Maybe you need to plot some points on the graph. Do you have any instructions for the assignment?
Answer:
27.6
Step-by-step explanation:
sin29=x/57
0.48480962=x/57
x≈27.6
The next 2 answers are: -2/5 and -3/5
Answer:
0.41 tons can be lifted
Step-by-step explanation:
The diameter d in inches of a rope needed to lift a weight of w tons is given by the formula d = 15w π .
This means that the diameter of the rope varies with the weight to be lifted. d is the dependent variable
π is a constant which is approximately 3.142
To determine the amount of weight that can be lifted with a rope with a diameter of 19.5 in, we substitute d = 19.5 into the given equation. It becomes
19.5 = = 15w ×3.142
19.5 = 47.13w
w= 19.5/47.13 = 0.41 tons
<h3>
Answer: 30.78181 meters</h3>
The value is approximate. Round that however you need to.
========================================================
Explanation:
- lowercase a = side opposite angle uppercase A
- lowercase b = side opposite angle uppercase B
- b = AC
Using the law of sines, we can say:
a/sin(A) = b/sin(B)
45/sin(30) = b/sin(20)
b/sin(20) = 45/sin(30)
b = sin(20)*45/sin(30)
b = 30.78181 approximately
You'll need to make sure your calculator is in degree mode.