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finlep [7]
3 years ago
10

A 1200 kg car accelerates from 0 m/s to 25 m/s in 10 seconds. how much work was done on the car by the net force?

Physics
1 answer:
Blizzard [7]3 years ago
5 0
Are there any answer choices

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Remember to include your data, equation, and work when solving this problem.
andrezito [222]

Answer:

F = 0.00156[N]

Explanation:

We can solve this problem by using Newton's proposed universal gravitation law.

F=G*\frac{m_{1} *m_{2} }{r^{2} } \\

Where:

F = gravitational force between the moon and Ellen; units [Newtos] or [N]

G = universal gravitational constant = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1= Ellen's mass [kg]

m2= Moon's mass [kg]

r = distance from the moon to the earth [meters] or [m].

Data:

G = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1 = 47 [kg]

m2 = 7.35 * 10^22 [kg]

r = 3.84 * 10^8 [m]

F=6.67*10^{-11} * \frac{47*7.35*10^{22} }{(3.84*10^8)^{2} }\\ F= 0.00156 [N]

This force is very small compare with the force exerted by the earth to Ellen's body. That is the reason that her body does not float away.

6 0
2 years ago
Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows t
Nezavi [6.7K]

Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the  

calculation of RT equivalent resistance

is:  

RT = R1 + R2 + R3

We replace the data of the statement in the previous expression and it remains:  

5 10 15 RT + R1 + R2 + R3 + +

We perform the mathematical operations that lead us to the result we are looking for:  

RT - 30Ω

5 0
2 years ago
Brianna pushes a 20 kg box with a force of 50N to achieve an acceleration of 2.5 m/s/s. In order to push a 30 kg box at the same
Elanso [62]

Answer:

She applies 75N of force

Explanation:

F=ma

50=20(2.5)

F=30(2.5)

F=75 N

5 0
2 years ago
Water flows through a horizontal pipe (from a wider area to narrow area section) and then out into the atmosphere at a speed v1
Darina [25.2K]

Answer:

V = 6.36 m³

Explanation:

For this exercise we will use fluid mechanics relations, starting with the continuity equation.

Let's write the flow equation

        Q = v₁ A₁

       

The area of ​​a circle is

        A = π r²

Radius is half the diameter

        A = π/4  d²

        Q = v₁ π/4 d₁²

        Q = π/ 4 15 0.03 2

        Q = 0.0106 m3 / s

The volume of water in t = 10 min = 10 60 = 600 s

        Q = V / t

        V = Q t

         V = 0.0106 600

          V = 6.36 m³

4 0
3 years ago
Current flows in a light detection device when _____ collide with its pn junction.
inysia [295]
The light detection device is also called photodetector. It <span>transforms any natural or artificial light source it encounters into sound.
</span>Current flows in a light detection device when light collide with its pn junction.
When light falls on the junction, a reverse current flows which is proportional to the illuminance. The linear response to light makes it an element in useful photodetectors<span> for some applications. It is also used as the active element in light-activated switches.</span>
7 0
3 years ago
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