Answer:
1.8 × 10² s
Explanation:
Let's consider the reduction that occurs upon the electroplating of copper.
Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)
We will establish the following relationships:
- 1 g = 1,000 mg
- The molar mass of Cu is 63.55 g/mol
- When 1 mole of Cu is deposited, 2 moles of electrons circulate.
- The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
- 1 A = 1 C/s
The time that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

Answer:
16974J of energy are required
Explanation:
The energy required is:
* The energy to heat solid water from -15°C to 0°C using:
q = m*S*ΔT
* The energy to convert the solid water to liquid water:
q = dH*m
* The energy required to increase the temperature of liquid water from 0°C to 75°C
q = m*S*ΔT
The first energy is:
q = m*S*ΔT
<em>m = Mass water = 25g</em>
<em>S is specific heat of ice = 2.03J/g°C</em>
<em>ΔT is change in temperature = 0°C - (-15°C) = 15°C</em>
q = 25g*2.03J/g°C*15°C
q = 761.3J
The second energy is:
q = dH*m
<em>m = Mass water = 25g</em>
<em>dH is heat of fusion of water = 80cal/g</em>
q = 80cal/g*25g
q = 2000cal * (4.184J/1cal) = 8368J
The third energy is:
q = m*S*ΔT
<em>m = Mass water = 25g</em>
<em>S is specific heat of water= 4.184J/g°C</em>
<em>ΔT is change in temperature = 75°C-0°C = 75°C</em>
q = 25g*4.184J/g°C*75°C
q = 7845J
The energy is: 7845J + 8368J + 761J =
16974J of energy are required
Answer:
The carbon atom in CO2 has two double bonds, one with each atom of oxygen. Therefore, the carbon's hybridization is sp. Determine the hybridization for the other atoms in the molecule. Each oxygen atom in CO2 has a single double bond with the carbon.
Answer:
The mass of S that reacted is 0.642g
Explanation:
In this case we have
⇒ mass of crucible and cover, 25.429g
⇒ mass of crucible, cover, and Pb, 29.465g
⇒ mass of crucible, cover and commass of crucible and coverpound formed, 30.107g
The mass of Pb reacted = mass of crucible, cover, and Pb - mass of crucible and cover = 29.465 - 25.429 = 4.036g
The mass of compound formed = mass of crucible, cover and commass of crucible and coverpound formed - mass of crucible and cover = 30.107 - 25.429g = 4.678g
The mass of S reacted = Mass of compound formed - mass of Pb reacted = 4.678 -4.036 = 0.642g
The mass of S that reacted is 0.642g