Answer :
YES, The precipitation reaction will occur.
Explanation : When we mix the aqueous solutions of Lead chloride and Ammonium sulfide a reaction will occur which is stated below :
![PbCl_{2} +(NH_{4}) _{2} S ----\ \textgreater \ PbS + 2[ (NH_{4})Cl]](https://tex.z-dn.net/?f=PbCl_%7B2%7D%20%2B%28NH_%7B4%7D%29%20_%7B2%7D%20S%20----%5C%20%5Ctextgreater%20%5C%20%20PbS%20%2B%202%5B%20%28NH_%7B4%7D%29Cl%5D%20)
The major product that is formed is Lead sulfate which is black in colour.
Once the reaction is complete one can observe a black precipitate getting obtained.
Answer:
Mass to moles: mass/molar mass=mole
Moles to mass: moles x molar mass = mass
Moles to particles:1mole = 6.022x10^23 particles
Particles to moles: 1 particle =1/(6.022x10^23) mole
Explanation:
Answer:
6
Explanation:
Formula: Al2O3
If we require 2Al2O3
We divide 2 by 3
Sorry for the shadow of phone and fingers.
Answer:
[NaOH} = 0.4 M
Explanation:
In a reaction of neutralization, we determine the equivalence point of the titration. In this case, we have a strong base and a strong acid.
(H₂SO₄, is considered strong, but the first deprotonation is weak)
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
As we have 2 protons in the acid, we need 2 OH⁻ from the base to form 2 molecules of water.
In the equivalence point we know mmoles of base = mmoles of acid
Let's finish the excersise with the formula
25 mL . M NaOH = 28.2 mL . 0.355M
M NaOH = (28.2 mL . 0.355M) / 25 mL → 0.400
Answer:
here
Explanation:
What is the total mass of $$3.01 x 10^23$$ atoms of helium gas?
✓ Well $$"Avogadro's number"$$ of helium atoms has a mass of $$4.0*g$$. Explanation: And $$"Avogadro's number"$$
