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3 years ago

Question 19 of 26

Chemistry

1 answer:

Alona [7]3 years ago

4 0

Answer:

3Mg(NO3)2(aq)+2Na3PO4(aq)⇒Mg3(PO4)2(s)+6NaNO3(aq)

Explanation:

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You place 12.0 milliliters of water in a graduated cylinder. Then you add 15.0 grams of metal to the water and the new water lev

Marrrta [24]

Answer:

<h3>The answer is 7.85 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

volume = final volume of water - initial volume of water

volume = 13.91 - 12 = 1.91 mL

We have

$density = \frac{15}{1.91} \\ = 7.853403141...$

We have the final answer as

Hope this helps you

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3 years ago

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What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chem

Ainat [17]

Answer: 0.002 M

Explanation:

The balanced chemical equation for ionization of $H_2SO_4$ in water is:

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

According to stoichiometry :

1 mole of $H_2SO_4$ ionizes to give =2 mole of $H^+$ ions

0.001 mole of $H_2SO_4$ ionizes to give = $\frac{2}{1}\times 0.001=0.002$ mole of $H^+$ ions

Thus $H^+$ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

4 0

2 years ago

Determine the grams of Iron(III) chloride produced if 22.5 g Iron reacts with Chlorine gas. First, balance the chemical equation

TEA [102]

22.5 because it still stays the same

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3 years ago

Please answer this correctly,,, This is a huge part of my grade. And who ever answers correctly will get brainliest!

chubhunter [2.5K]

Answer:

I belive it's the black chair because they were asking which chair experienced the most force in the begining and the black chair had the most force given.

8 0

3 years ago

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A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th

tatyana61 [14]

Answer : The partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

Explanation :

As we are given 75 % $CO_2$ and 25 % $N_2$ in terms of volume.

First we have to calculate the moles of $CO_2$ and $N_2$ .

$\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole$

$\text{Moles of }N_2=\frac{\text{Volume of }N_2}{\text{Volume at STP}}=\frac{25}{22.4}=1.12mole$

Now we have to calculate the mole fraction of $CO_2$ .

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}$

$\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75$

Now we have to calculate the partial pressure of the $CO_2$ gas.

$\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}$

$\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}$

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

3 0

3 years ago