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2 years ago

8

A ray of light strikes a boundary between two transparent materials, and there is no transmitted ray, as shown in the figure. Wh

at can you conclude about the indices of refraction of these two materials

1 answer:

arlik [135]2 years ago

8 0

Answer:q

Explanation:

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Which shows the correct angle of reflection given the incident ray shown? <br>

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Actually Welcome to the Concept of the Rays of light.

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3 years ago

Help with electrician homework

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3 years ago

12*3a car is stopped at a traffic light. it then travels along a straight road so that its distance from the light is given by w

Digiron [165]

Missing parts in the text of the exercise:
- The distance from the traffic light is given by $x(t) = bt^2 -ct^3$ , where $b=2.4 m/s^2$ and $c=0.13 m/s^3$

Solution:

part a) <span>calculate the average velocity of the car for the time interval t=0 to t=8.0 s
- The average velocity is given by the ratio between the distance covered in the time interval:
</span> $v_{ave} = \frac{x(8.0 s)-x(0 s)}{8.0 s-0 s}$
x(0 s), the distance covered after t=0 s, is zero, while the distance after t=8.0 s is
$x(8.0 s)=b(8 s)^2-c(8 s)^3 = (2.4 m/s^2)(8 s)^2 -(0.13 m/s^3)(8 s)^3=$
$=87.04 m$
Therefore, the average velocity is
$v_{ave}= \frac{x(8.0 s)-x(0)}{8.0s-0}= \frac{87.04 m}{8.0s}= 10.88 m/s$

part b) <span>calculate the instantaneous velocity of the car at t=0, t=4.0 s and t=8.0 s
- The instantaneous velocity can be found by performing the derivation of x(t):
</span> $v(t) = \frac{dx(t)}{dt}=2bt-3ct^2$
<span>So now we just have to substitute t=0, t=4 s and t=8 s:
- t=0: v(0)=0
- t=4 s: </span> $v(4.0 s)=2(2.4 m/s^2)(4.0 s)-3(0.13 m/s^2)(4.0s)^2=12.96 m/s$
- t=8 s: $v(8.0 s)=2(2.4 m/s^2)(8.0 s)-3(0.13 m/s^2)(8.0s)^2=13.44 m/s$

part c) <span>how long after starting from rest is the car again at rest?
- To solve this part we must find the value of t for which v(t)=0, so:
</span> $2bt-3ct^2=0$
$t(2b-3ct)=0$
<span>The first solution is t=0 s, which corresponds to the beginning of the motion, so we are not interested in this value. The second solution is
</span> $t= \frac{2b}{3c}= \frac{2\cdot 2.4 m/s^2}{3 \cdot 0.13 m/s^3}=12.31 s$
<span>and this is the time at which the car is at rest again.</span>

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3 years ago

At one instant, point P is 7.30 to the left of a proton that is moving at 3.10 km/s in vacuum. The point and velocity vector lie

o-na [289]

Answer:

the unit vector points from the point charge toward where the field is measured(from proton to point P)

Explanation:

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4 years ago

Protons and neutrons in an atom are held together by _____.

marysya [2.9K]

Protons and neutrons in an atom are held together by a nuclear energy also called the strong force.

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4 years ago