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2 years ago

What are some ways to separate a mixture?

1 answer:

3 0

la separación mecánica de un sólido de grano grueso, insoluble, en un líquido; consiste en verter cuidadosamente el líquido, después de que se ha sedimentado el sólido. Por este proceso se separan dos líquidos miscibles, de diferente densidad, por ejemplola separación de un sólido disuelto en un líquido, por calentamiento, hasta que hierve y se transforma en vapor. Como no todas las sustancias se evaporan con la misma rapidez, el sólido disuelto se obtiene en forma pura, agua y aceite.

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1.imagine you were able to throw a ball in a frictionless environment such as outer space.once you let go of the ball,what will

Scorpion4ik [409]

Imagine you were able to throw a ball in a frictionless environment
such as outer space. Once you let go of the ball, it will travel forever
in a straight line, and at a constant speed. (At least until it bumps into
something.)

A car accelerates down the road. The reaction to the tires pushing
on the road is the road pushing on the tires.

5 0

3 years ago

A 50-kg copper block initially at 140Â°c is dropped into an insulated tank that contains 90 l of water at 10Â°c. Determine the f

xxMikexx [17]

Answer:

$T_f=24.71$

Explanation:

From the question we are told that:

Mass of block $m=50$

Temperature of block $T_b =140 \textdegree C$

Volume of water $V= 90L$

Temperature of water $T_w=10 \textdegree C$

Density of water $\rho=1000kg/m^3$

Specific heat of water $C_w=4.18KJ/kg-k$

Specific heat of copper $C_p=0.96KJ/kg-k$

Generally the equation for equilibrium stage is mathematically given by

$mC_p(T_b-T_f)=\rho*VV*c(T_f-T_w)$

$50*0.96(140-T_f)=1000*90*10^-3*c_w(T_f-10)$

$48(140-T_f)=376.2(T_f-10)$

$140-T_f=7.8375(T_f-10)$

$140-T_f=7.8375T_f-78.375$

$-8.8375T_f=-218.375$

$T_f=\frac{-218.375}{-8.8375}$

$T_f=24.71$

6 0

2 years ago

Help please I do not understand

ahrayia [7]

What don’t you understand? If you haven’t uploaded anything

3 0

2 years ago

A) Show that the surface temperature of a star can be inferred from measurements of blackbodyfluxes at two different frequencies

Roman55 [17]

Answer:

The answers to the questions have been solved in the attachment.

Explanation:

The answers to part a to e are all contained in the attachment. For answer part b, temperature and frequency were assumed to be fixed or constant. V² is directly proportional to T telling us that variation in T gives us a square in the frequency variation. This tells us why it is difficult when both frequencies are on this side of the black body.

3 0

2 years ago

calculate the resistance of a wire 150cm long and diameter 2.0mm constructed from an alloy of resistivity 44*10-⁸Ωm

Ghella [55]

Answer:

R = 0.21 Ω

Explanation:

the formula:

R = r x l/A

R = (44 x 10-⁸ Ωm) x 1.5 / (π x (1 x 10-³ m)²)

R = 6.6 x 10-⁷ / 3.14 x 10-⁶

R = 0.21 Ω

8 0

2 years ago