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erik [133]
2 years ago
14

The song Arirang is an example of korean F_L_ _O N_​

Physics
1 answer:
sergij07 [2.7K]2 years ago
7 0
Folk song

(Word cap filler)
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List any similarities between discovered exoplanets and planets in our solar system.
gregori [183]

Answer:

1. Revolve around a point

2. Formed from dust and gas particles

3. Exoplanets and associated star orbit a common center of mass  

4. Composed of gases found in Jupiter and Saturn

3 0
3 years ago
Pls help i have 5 minutes
anyanavicka [17]

Number order:

5, 4, 3, 2, 1

7 0
4 years ago
Read 2 more answers
If the ankylosaurs starts running and accelerates at 1.3m/s^2 for 3 seconds how far does he make it before the velociraptor catc
sveta [45]

Acceleration is the change of velocity, and velocity is the change of distance. The opposite of finding change, or differentiation, is integration.

Acceleration = 1.3 m/s²

Velocity: ∫ 1.3 dx = 1.3x + c m/s

Distance: ∫ 1.3x dx = 1.3x²/2 + c m

Distance run: 1.3*3²/2 = 5.85 m

<em>What</em><em> </em><em>bad</em><em> </em><em>thing</em><em> </em><em>happened</em><em>?</em>

7 0
3 years ago
Male Rana catesbeiana bullfrogs are known for their loud mating call. The call is emitted not by the frog's mouth but by its ear
Sidana [21]

Answer:

The amplitude of the eardrum's oscillation is 6.65×10^-13 m.

Explanation:

Given data:

The sound has a frequency of 262 Hz

The sound level is 84 dB

The air density is 1.21 kg/m^3

The speed of sound is 346 m/s

Solution:

As, Intensity of sound is given by,

I = Io×10^(s/10 db)

I = 2×π^2×ρ×v×f^2×Sm^2

Thus,

Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)

Now, put the values,

Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )

Sm = √(2.51×10^-4 / 5.66×10^8)

Sm = √0.443×10^-12

Sm = 6.65×10^-13 m.

8 0
3 years ago
A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of ac
lions [1.4K]

Answer:

x = 95 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} =v_{o} +a*t

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

Now we can find the acceleration

19 = 0 *a*(10)

a = 1.9 [m/s]

With the second equation we can find the distance:

v_{f} ^{2} =v_{o} ^{2} +(2*a*x)

where:

x = distance [m]

(19)² = (0)² + (2*1.9*x)

3.8*x = 361

x = 95 [m]

7 0
3 years ago
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