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Mandarinka [93]
3 years ago
13

A 74.1 kg high jumper leaves the ground with

Physics
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:

4.80 m

Explanation:

We are given the mass of the high jumper, its initial velocity, and the acceleration of gravity. We are trying to find the vertical displacement of the high jumper.

Let's set the upwards direction to be positive and the downwards direction to be negative.

List out the relevant known variables.

  1. v₀ = 9.7 m/s
  2. a = -9.8 m/s²
  3. Δx = ?

We still need one more variable in order to use the constant acceleration equations. Since we are trying to find the max height of the jumper, we can use the fact that at the top of its trajectory, its final velocity will be 0 m/s.

    4. v = 0 m/s

Using these four variables, let's find the constant acceleration equation that contains these variables:

  • v² = v₀² + 2aΔx

Substitute the known values into the equation and solve for Δx.

  • (0)² = (9.7)² + 2(-9.8)Δx
  • 0 = 94.09 + (-19.6)Δx
  • -94.09 = -19.6Δx
  • Δx = 4.80

The high jumper can jump to a max height of 4.80 m.

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Moving company uses a machine to raise a 900 Newton refrigerator to the second floor of a building machine consists of a single
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Identify the relationship between the two quantities in the given question as causation or
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A scooter is traveling at a constant speed v when it encounters a circular hill of radius r = 480 m. The driver and scooter toge
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Answer:

68.585m/sec , 779.1 N

Explanation:

To feel weightless, centripetal acceleration must equal g (9.8m/sec^2). The accelerations then cancel.

From centripetal motion.

F =( mv^2)/2

But since we are dealing with weightlessness

r = 480m

g = 9.8m/s^2

M also cancels, so forget M.

V^2 = Fr

V = √ Fr

V =√ (9.8 x 480) = 4704

= 68.585m/sec.

b) Centripetal acceleration = (v^2/2r) = (68.585^2/960) = 4704/960

= 4.9m/sec^2.

Weight (force) = (mass x acceleration) = 159kg x (g - 4.9)

159kg × ( 9.8-4.9)

159kg × 4.9

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The resistance of a very fine aluminum wire with a 20 μm × 20 μm square cross section is 1200 Ω . A 1200 Ω resistor is made by w
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Explanation:

The given data is as follows.

         Resistance (R) = 1200 ohm,     Area (A) = 20 \times 10^{-6} m (as 1 \mu m = 10^{-6} m)

            Diameter (d) = 2.3 mm = 2.3 \times 10^{-3} m

First, we will calculate the length as follows.

            R = \rho \frac{L}{A}

Here,  \rho = resistivity of aluminium = 2.65 \times 10^{-8}

Putting the given values above and we will calculate the value of length as follows.

               R = \rho \frac{L}{A}

             1200 = 2.65 \times 10^{-8} \times \frac{L}{20 \times 10^{-6}}

               L = 9.056 \times 10^{5}

As the circumference of circular wire = 2 \pi r

or,                                                          = 2 \times \pi \times \frac{d}{2}  

                                                              = \pi \times d

And, number of turns will be calculated as follows.

             No. of turns × Circumference = Length of wire

              No. of turns × 3.14 \times 2.3 \times 10^{-3} = 9.056 \times 10^{5}

                               = 1.25 \times 10^{8}

Thus, we can conclude that 1.25 \times 10^{8}  turns of wire are needed.

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