In the given equation :
If three physical quantities is to be added or subtracted, they must have same dimensions.
So, dimension of y = dimension of c(t²)
And we already know,
- y = M⁰L¹T⁰ [ since it represents distance/length ]
- t = M⁰L⁰T¹ [ since it represents time ]
( by squaring )
Now, we need to calculate dimension and unit of c :
Now, we got the dimension of c as :
So, it's SI unit will be :
[ since SI unit of length/distance = m, and SI unit of Time = sec, hence SI unit of T² = s² ]
Answer:
Factor = 8.77
Explanation:
Fraction of collision with energy greater than or equal to the activation energy can be given by the formula:
R = 8.314 J/mol.K
When Temperature = 34⁰C = 34 + 273 = 307 K
When Temperature = 52⁰C = 52 + 273 = 325 K
Factor = 8.77
Answer:
q_enclosed = 759.57 nC
Explanation:
A cylindrical shell of radius 7.00 cm and length 2.48 m has its charge uniformly distributed on its curved surface. The magnitude of the electric field at a point 15.3 cm radially outward from its axis (measured from the midpoint of the shell) is 36.0 kN/C.
Find the value of the net charge on the shell.
Given that Length L of the cylinder shell is 248 cm and the diameter d is 7.0 cm. We can approximate L >> d. This approximation concludes that the cylindrical shell is infinitely long, when we are examining the Electric fiel strength E from the ends of the shell.
Hence,
E = q_enclosed / 2*pi*ε_o *r*l
Where r = d / 2, then
q_enclosed = E*(2*π*r*l*ε_o)
q_enclosed = (36000)*(2*π*8.85*10^-12 *0.153*2.48)
q_enclosed = 759.57 nC
Answer:
a) 8.85 kJ
b) 7.85 kJ
c) 6.85 kJ
Explanation:
we will use the energy conservation theorem for all of the stages
for stage 1:
the initial velocity and the potential gravitational energy at the bottom is zero:
for stage 2:
the velocity is constant so there is no change in the kinetic energy, so there is change only on the potential gravitational energy:
for stage 3:
there is a change for both, gravitational and kinetic energy so: