Answer:
V = 4.63 m/s
V = 11.31 m/s
Explanation:
Given,
The distance traveled by the bus, towards north, d = 2.5 km
= 2500 m
The time taken by the trip is, t = 9 min
= 540 s
The velocity of the bus,
V = d / t
= 2500 / 540
= 4.63 m/s
At another point, the bus travels at a constant speed of v = 18 m/s
Therefore the velocity becomes
V = (4.63 + 18)/2
= 11.31 m/s
Hence, the velocity of the bus, V = 11.31 m/s
Answer:
1.8m
Explanation:
Let the Elastics of the steel ASTM-36 
The strain of the bar when subjected to 150 MPa is

Therefore, if the bar elongates by 1.35 mm, then the original length L would be:

or 1.8m
Answer:
I'm pretty sure its 3m/s^2 for the acceleration but I don't know the force part sorry .
Explanation:
15m/s - 0m/s divided by 5 s = 3m/s
I'm no expert or anything so I could be wrong but this is the best I can give you. Sorry
F=ma
Tension - weight = mass x acceleration
T - 5(9.81) = 5 x 1
T = 5 + 5(9.81)
T = 54.05 N
T ≈ 54 N
G is the gravitational constant, which is approximately 6.6x10^-11 Nm/s^2. It has the same value regardless of the masses of both objects or the distance between them.