Answer:
The veins that carry oxygenated bloof back into the heart are the pulmonary arteries.
Explanation:
Oxygen-rich blood flows from the lungs back into the left atrium (LA), or the left upper chamber of the heart, through four pulmonary veins. Oxygen-rich blood then flows through the mitral valve (MV) into the left ventricle (LV), or the left lower chamber.
Answer:
- <em>The net charge of the ionic compound calcium fluoride is </em><u><em>zero (0).</em></u>
<em>Explanation:</em>
<em>Ionic compounds,</em> such as covalent ones, have zero net charge; this is, they are neutral.
Substances with net positive charge are cations and substances with net negative charge are anions.
The charges in the <em>ionic compound calcium flouride</em> are distributed in this way:
- Calcium charge: Ca²⁺: this is, each calcium ion has a 2 positive charge
- Fluoride charge: F⁻: each fluoride ion has a 1 negative charge.
- Then, the <em>net charge</em> is: 1 × (2+) + 2 × (1-) = +2 - 2 = 0.
So, a two positve charge, from one calcium ion, is equal to two negative charges, from two fluoride tions, yielding a <u>zero net charge</u>.
Answer:
6L
Explanation:
<em>if it's 3L per 200kPa</em>
then it would be;
4L per 300kPa
5L per 400kPa
6L per 500kPa
that's how i'd work it out in my head, hope it helps, but not sure though!
Answer:- 1467 K
Solution:- It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.
Given: 
V = 75.0 mL = 0.0750 L
P = 116.8 kPa
We know that, 101.325 kPa = 1 atm
So, 
= 1.15 atm
R is universal gas constant and it's value is 
.
T = ?
Let's plug in the values in the equation and solve it for T.
0.08625 = 0.00005878(T)
T = 1467 K
So, the temperature of the light bulb would be 1467 K.
