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baherus [9]
2 years ago
11

Examine the roller coaster track above. Assume there is negligible friction as the roller coaster moves from position A to posit

ion F. Also assume that the roller coaster has minimal kinetic energy at point A. Create three different models below to describe the kinetic energy, the potential energy, and the total energy of the roller coaster at point E. Examples of models include, but are not limited to: pie charts, bar graphs, equations, textual descriptions, and analogies.

Physics
1 answer:
anyanavicka [17]2 years ago
5 0

At point E

  • the kinetic energy of the rollercoaster is small compared to the potential energy
  • the potential energy is greater than the kinetic energy
  • the total energy is a mixture of potential and kinetic energy

<h3>What is the energy of the roller coaster at point E?</h3>

The energy of a roller coaster could either be potential energy, kinetic energy or a combination of both potential and kinetic energy.

Using analogies, the energy of the roller coaster at point E can be compared to a falling fruit from a tree which falls onto a pavement and is the rolling towards the floor. Point E can be compared to the midpoint of the fall of the fruit.

At point E

  • the kinetic energy of the rollercoaster is small compared to the potential energy
  • the potential energy is greater than the kinetic energy
  • the total energy is a mixture of potential and kinetic energy

In conclusion, the energy of the rollercoaster at E is both Kinetic and potential energy,

Learn more about potential and kinetic energy at: brainly.com/question/18963960

#SPJ1

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An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
A tourist averaged 82km/hr for a 6.5h trip in her volkswagen. how far did she go?
Whitepunk [10]
82 ÷ 6.5 = 12.615384615384... repeating
round = 12.6
12.6 · 6.5 = 81.9
round = 82
She went an average of 12.6 km an hour
Hope this helps! ;)
4 0
3 years ago
Which is not a property of a mineral?<br>O magnetism<br>o cleavage<br>O color<br>o reflection​
yKpoI14uk [10]
Reflection. I used the process of elimination. Cleavage and color are properties of a mineral and magnetism is a property as well you just can’t find strong traces of it in all minerals. But it’s there no matter how weak or strong it’s attraction is drawn to magnetic fields.
7 0
3 years ago
Which of these samples of water has the most internal energy?
Setler [38]

Answer:

1kg steam will have the maximum energy

3 0
3 years ago
Each wheel of a 320 kg motorcycle is 52 cm in diameter and has rotational inertia 2.1 kg m2 . The cycle and its 75 kg rider are
Amiraneli [1.4K]

Answer:

The value is  h  = 32.91 \  m

Explanation:

From the question we are told that

    The diameter of each wheel is  d =  52 \ cm  =  0.52 \  m

    The mass of the motorcycle is  m  =  320 \ kg

    The rotational kinetic inertia is  I  =  2.1 \  kg \  m^2

    The  mass of the  rider is  m_r =  75 \ kg

     The  velocity is  v  =  85 \  km/hr = 23.61 \  m/s

      Generally the radius of the wheel is mathematically represented as

      r =  \frac{d}{2}

=>     r =  \frac{0.52}{2}

=>    r =  0.26 \  m

Generally from the law of energy conservation

     Potential energy  attained  by  system(motorcycle and rider )  =  Kinetic  energy of the system  +  rotational kinetic energy of  both wheels of the motorcycle

=>  Mgh  =  \frac{1}{2}  Mv^2  +   \frac{1}{2}  Iw^2  +  \frac{1}{2}  Iw^2

=>    Mgh  =  \frac{1}{2}  *  Mv^2  +  Iw^2

Here  w is the angular velocity which is mathematically represented as

     w =  \frac{v }{r }

So

    Mgh  =  \frac{1}{2}  *  Mv^2  +  I \frac{v}{r} ^2

Here M  =  m_r +  m

         M  =  320 + 75

          M  = 395 \  kg

395 *  9.8 *  h  =   0.5    *   395 *  (23.61)^2 +  2.1  *[\frac{ 23.61}{ 0.26} ] ^2

=>   h  = 32.91 \  m

   

7 0
4 years ago
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