We got coefficient of
friction uk = 0.51<span>
Mass m = 1500 kg
normal force on the car = weight of the car = 1500 * 9.8 N =
14700 N
and the force of friction on the car, f = uk * normal force =
0.51 * 14700 N = 7497 N
taking Acceleration a = -f/m = -7497/1500 = -4.998 m/s^2
Displacement s = 66 m
Final velocity v = 0
Initial velocity u = ?
v^2 = u^2 + 2as
<span>0 = u^2 - 2 * 4.998 * 66
<span>u = 25.69 m/s </span></span></span>
Answer:7,500J
Explanation:
Work done=force× distance
at the top most point if Rupert will not fall then normal force at the top point is almost zero for minimum speed
so here we can say

now if





so above will be the minimum speed
Answer:
showm
Explanation:
Consider a dipole having magnetic moment 'm' is placed in magnetic field
then the torque exerted by the field on the dipole is


Now to rotate the dipole in the field to its final position the work required to be done is




Minimum energy mB is for the case when m is anti parallel to B.
Minimum energy -mB is for the case when m is parallel to B.
Answer: if the mass is doubled, the force of gravity is doubled, meaning it decreases. If the distance is doubled, the force of gravity is 1/4 as strong as before
Explanation: