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zaharov [31]
3 years ago
5

A spacecraft is traveling in interplanetary space at a constant velocity. What is the estimated distance traveled by the spacecr

aft in 9.50 seconds?
Physics
2 answers:
aniked [119]3 years ago
7 0
You haven't said what the constant velocity is, so the best answer that
I can give you is

    Distance = (9.5) times (magnitude of the velocity, in meters per second) .
zhuklara [117]3 years ago
5 0
What is the constant velocity? 
<span>We need that number in order to solve the problem
</span>Or
<span>It has a graph in which it describes the different acceleration</span>
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A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 6.55x10-2 kg/s. The density of the gasoline is 740
klasskru [66]

Answer:

speed = 3.95 m/s

Explanation:

area = π x radius^2

area = π x (2.67 x 10^-3)^2

volume flow rate = area x speed

volume / time = area x speed

density = mass / volume

volume = mass / density

<u>mass / (density x time) = area *speed</u>

mass flow rate = mass / time

<u>mass flow rate / density = area x speed</u>

6.55 x 10^-2 / 740 = pi * (2.67 x 10^-3)^2 * speed

speed =8.8514 x 10-5 /2.2396 x 10-5 m/s

speed = 3.95 m/s

6 0
3 years ago
An object traveling at constant speed v in a circle of radius R has an acceleration am 5 m/s2. If both R and v are doubled, what
MakcuM [25]

Answer:

im pretty sure its 10 m/s but its kinda hard sorry

Explanation:

7 0
3 years ago
An experimental apparatus has two parallel horizontal metal rails separated by 1.0 m. A 3.0 Ω resistor is connected from the lef
Blizzard [7]

Answer:

The induced current and the power dissipated through the resistor are 0.5 mA and 7.5\times10^{-7}\ Watt.

Explanation:

Given that,

Distance = 1.0 m

Resistance = 3.0 Ω

Speed = 35 m/s

Angle = 53°

Magnetic field B=5.0\times10^{-5}\ T

(a). We need to calculate the induced emf

Using formula of emf

E = Blv\sin\theta

Where, B = magnetic field

l = length

v = velocity

Put the value into the formula

E=5.0\times10^{-5}\times1.0\times35\sin53^{\circ}

E=1.398\times10^{-3}\ V

We need to calculate the induced current

E =IR

I=\dfrac{E}{R}

Put the value into the formula

I=\dfrac{1.398\times10^{-3}}{3.0}

I=0.5\ mA

(b). We need to calculate the power dissipated through the resistor

Using formula of power

P=I^2 R

Put the value into the formula

P=(0.5\times10^{-3})^2\times3.0

P=7.5\times10^{-7}\ Watt

Hence, The induced current and the power dissipated through the resistor are 0.5 mA and 7.5\times10^{-7}\ Watt.

6 0
3 years ago
Read 2 more answers
A wagon full of manure accidentally rolls down a driveway for 5.0m while a person pushes against the wagon with a force of 420 N
Cerrena [4.2K]

Answer:

2100 J

Explanation:

Parameters given:

Force acting on the object, F = 420 N

Distance moved by object, d = 5m

The change in kinetic energy of an object is equal to the work done by a force acting on the object:

W = F * d

∆KE = F * d

∆KE = 420 * 5

∆KE = 2100 J

8 0
3 years ago
Read 2 more answers
Which of the following is equivalent to 140 centiliters?
tekilochka [14]
D, 0.140 liters! Hang on a sec and I'll show you a trick I use.
7 0
3 years ago
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