Answer:
Q = 62383.44 Joules
Explanation:
Given that,
Mass of water, m = 710 gm
Initial temperature of water, 
Final temperature of water, 
The specific heat capacity of liquid water is, 
Heat transferred is given by :
Q = 62383.44 Joules
So, the amount of heat transferred is 62383.44 Joules. Hence, this is the required solution.
Answer:
Explanation:
you mean deceleration right ? because the acceleration is 250m/s
Answer:
Evaporative Water Loss = 2 kg
Explanation:
According to the given condition, the water entering the body must be equal to the water leaving the body. Therefore,
Water Entering the Body = Water Leaving the Body
Feed Water + Drinking Water + Metabolic Water = Urine Water + Evaporative Water Loss
using the given values:
1 kg + 5 kg + 0.5 kg = 4.5 kg + Evaporative Water Loss
Evaporative Water Loss = 1 kg + 5 kg + 0.5 kg - 4.5 kg
<u>Evaporative Water Loss = 2 kg</u>
