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2 years ago

Radiation from the sun hits Earth unequally and is absorbed by different materials in varying amounts. This is called

Physics

1 answer:

GenaCL600 [577]2 years ago

4 0

Answer:

sorry I don't know what is the answer of this question

sorry for that sorry

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A garden hose having with an internal diameter of 1.1 cm is connected to a (stationary) lawn sprinkler that consists merely of a

trapecia [35]

Answer:

Water leaves the sprinkler at a speed of 2.322 m/sec

Explanation:

We have given internal diameter of the garden $d_1=1.1cm$

Speed of water in the hose is $v_1=0.95m/sec$

Number of holes n = 22

Diameter of each holes $d_2=15cm$

According to continuity equation $A_1v_1=A_2v_2$

$d_1^2\times v_1=22\times d_2^2v_2$

$1.1^2\times 0.95=22\times 0.15^2\times v_2$

$v_2=2.322m/sec$

So water leaves the sprinkler at a speed of 2.322 m/sec

6 0

3 years ago

Two balloons are charged with an identical quantity and type of charge: -6.25 nanoCoulombs (10-9). They are held apart at a sepa

xenn [34]

Answer:

force between both the balloons is $9.23\times 10^{-7}N$

Explanation:

It is given charge on both balloons are same and equal to $q=-6.25\times 10^{-9}C$

Separation between both the balloons $r=61.7cm=0.617m$

According to Coulomb's law force between two charges is given by

$F=\frac{1}{4\pi \epsilon _0}\frac{q^2}{r^2}=\frac{Kq^2}{r^2}$

Therefore force is equal to

$F=\frac{9\times 10^9\times (-6.25\times 10^{-9})^2}{0.617^2}$

$F=9.23\times 10^{-7}N$

So force between both the balloons is $9.23\times 10^{-7}N$

3 0

3 years ago

A woman can read the large print in a newspaper only when it is at a distance of 55 cm or more from her eyes.

serious [3.7K]

Answer:

Farsightedness (hyperopic)

2.79 D

Explanation:

When a person cannot see something which is close to their eyes this condition is known as farsightedness. She should use a convex lens to correct her eye sight.

u = Object distance = 22-2.7 = 19.3 cm

v = Image distance = -55+2.7 = -52.3 cm

f = Focal length

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{19.3}+\frac{1}{-52.3}\\\Rightarrow \frac{1}{f}=\frac{3300}{100939}\\\Rightarrow f=\frac{100939}{3300}=30.58\ cm$