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pochemuha
3 years ago
8

Two balloons are charged with an identical quantity and type of charge: -6.25 nanoCoulombs (10-9). They are held apart at a sepa

ration distance of 61.7 cm (make sure to use METERS!). Determine the magnitude of the electrical force of repulsion between them.
Physics
1 answer:
xenn [34]3 years ago
3 0

Answer:

force between both the balloons is 9.23\times 10^{-7}N  

Explanation:

It is given charge on both balloons are same and equal to q=-6.25\times 10^{-9}C

Separation between both the balloons r=61.7cm=0.617m

According to Coulomb's law force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q^2}{r^2}=\frac{Kq^2}{r^2}

Therefore force is equal to

F=\frac{9\times 10^9\times (-6.25\times 10^{-9})^2}{0.617^2}

F=9.23\times 10^{-7}N

So force between both the balloons is 9.23\times 10^{-7}N

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