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jenyasd209 [6]
3 years ago
11

Assume that 4 molecules of nitrogen and 9 molecules of hydrogen are present? after complete reaction, how many molecules of ammo

nia are proceded?
Chemistry
1 answer:
Anastasy [175]3 years ago
5 0
<span>2<span>N2</span>+3<span>H2</span>→2N<span>H3

That's the balanced equation. As shown, 4 molecules of N2 would react with 12 molecules of H2. Since not that much H2 molecules exist, then it would serve as the limiting reactant. Therefore:

9 mol H2 * (2NH3 / 3H2) = 6 molecules of ammonia
</span></span>
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Answer:

1. SOCl2/pyridine

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Explanation:

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This is then followed by the addition of NH3 is subsequently added followed by reduction using LiAlH4 which reduces the carbonyl carbon to an alkane. addition of water completes the mechanism and leads to the formation of the product.

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Which best describes what happens when 50 mL of 0.0010M CaCl2 is added to 50 mL of 0.010M Na2SO4? (The Ksp of CaSO4 = 2.4 × 10–5
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When the solutions are diluted in half:
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8 0
3 years ago
Which of these statements is true?
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Answer:

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