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Snowcat [4.5K]
3 years ago
15

8.7g+15.43g+19g? 853.2L-627.443L? 5.47m+11m+87.300m?

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

the god ran down the street

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In a five-fold serial dilution of a 20 ug/mL solution, all tube dilutions are 1/5. What is the substance concentration in the th
sergij07 [2.7K]

Answer:

In the third tube, the concentration is 0.16 ug/mL

Explanation:

In the first step, the solution is diluted by 5. Then, the concentration will be

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This solution is then diluted again by 5 and the concentration in the third tube will be then:

0.8 ug/mL / 5 = <u>0.16 ug/mL </u>

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Another way to calculate this is to divide the original concentration by the dilution factor ( 5 in this case) elevated to the number of dilutions. In this case:

Concentration in the third tube = 20 ug/mL / 5³ = 0.16 ug/mL

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There are often not more than one or two independent variables tested in an experiment.

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i think that the answer would be 7 because 8 or less is for 1 shell so I think that it makes most sence

Explanation:

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