What is the empirical formula for a compound if 300. 00 g of it is known to contain 82. 46224 g of molybdenum, 45. 741 g of chlo
1 answer:
the empirical formula for a compound is Mo2Br5Cl3.
The empirical components of a compound are the best entire quantity ratio of atoms of every detail within the compound. it's miles decided using statistics from experiments and therefore empirical. as an example, the molecular formula of glucose is C 6H 12O 6 however the empirical formulation is CH 2O.
An Empirical formula is the chemical components of a compound that offers the proportions (ratios) of the elements present in the compound however no longer the real numbers or arrangement of atoms. This will be the lowest complete range ratio of the elements within the compound.
The empirical method of a compound gives the only ratio of the range of various atoms gift, while the molecular formula gives the actual range of each distinctive atom found in a molecule. If the components is simplified then it is an empirical components.
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Answer:
I have solved your problem
Explanation:
Answer:
See Below.
Explanation:
Recall that molarity is defined by moles of solute over liters of solution (mol/L).
Therefore, to make 90.0 mL of 2.0 M MgSO₄, we will need:
Convert this amount to grams. The molecular weight of MgSO₄ is 120.38 g/mol:
Therefore, to make the solution, we can add 22 grams of MgSO₄ into a graduated cylinder, then mix and dilute the solution with distilled water until we reach 90.0 mL.