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Wittaler [7]
3 years ago
13

A baseball has a mass of 135 grams and a softball has a mass of 270 grams. In which of the following situations would they have

the same momentum?
Chemistry
2 answers:
Sauron [17]3 years ago
3 0
The baseball is thrown twice as fast as the softball in the same direction.
natka813 [3]3 years ago
3 0

Answer:

The baseball is thrown twice as fast as the softball in the same direction.

Explanation:

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A sample of fluorine gas exerts a pressure of 900 mmHg. When the pressure is changed to 1140 mmHg, the volume is 250 mL. What wa
UNO [17]
Let's use Boyle's Law here. P1*V1 = P2*V2
Given: (assuming that there are decimals at the end for Sig Figs)
P1 = 900.mmHg
P2 = 1140.mmHg
V1 = ???
V2 = 250.mL

900.mmHg* ??? = 1140.mmHg * 250.mL
??? = 1.27*250.mL
??? = 318.mL

Therefore, the original volume is 318mL.
8 0
3 years ago
How many moles in 28.0 grams of Oxygen
anastassius [24]

Answer:

1.) 28.0 grams of oxygen28 grams (1 mole/16 grams per mole)=1.75 moles oxygen2.)5.0 moles of Iron5 moles(55.845 grams/1 mole)=279.225 grams Iron3.) 452 grams Argon452 grams(1 mole/39.948 grams)=11.315 moles Argon4.) 16.5 moles Hydrogen16.5 moles(1.01 grams/1 mole)=16.665 grams Hydrogen

Explanation:

3 0
3 years ago
An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci
lapo4ka [179]

Answer:

<u>Optical purity = 76.9231 %</u>

<u>Specific rotation of mixture = - 97.6923 °</u>

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

S enantiomer = 1.5 g

Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

[R] = 11.5 g/L

[S] = 1.5 g/L

Enantiomeric excess = \frac {Excess}{Total\ Concentration}\times 100 = \frac {11.5-1.5}{11.5+1.5}\times 100 = 76.9231 %

<u>Optical purity = 76.9231 %</u>

Also,

Optical purity = \frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100

Optical rotation of pure enantiomer = −127 °

76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100

<u>Specific rotation of mixture = - 97.6923 °</u>

6 0
3 years ago
How could we stop an asteroid that we know was going to hit Earth?<br><br><br> Pls help ASAP
myrzilka [38]

Answer:

An object with a high mass close to the Earth could be sent out into a collision course with the asteroid, knocking it off course. When the asteroid is still far from the Earth, a means of deflecting the asteroid is to directly alter its momentum by colliding a spacecraft with the asteroid.

Hope it helps!!

5 0
3 years ago
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Sholpan [36]

Answer:

D.

atomic modifier

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3 years ago
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