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melisa1 [442]
2 years ago
6

A reaction rate increases by a factor of 655 in the presence of a catalyst at 37°C. The activation energy of the original pathwa

y is 106 kJ/mol. What is the activation energy of the new pathway, all other factors being equal? Group of answer choices 89.3 kJ/mol 16,600 kJ/mol 89.3 J/mol 16,600 J/mol
Chemistry
1 answer:
irinina [24]2 years ago
5 0

For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway  is mathematically given as

Ea2=89.28JKoule/mol

<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>

Generally, the equation for the rate constant  is mathematically given as

K=Ae^{Ea1/Rt}

Therefore

\frac{1}{655}=\frac{1}{8.31*3.10}(Ea2-105000)

Ea2=89286.083Joule/mol

In conclusion, the activation energy

Ea2=89.28JKoule/mol

Read more about Energy

brainly.com/question/13439286

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<h3>What is hydrocarbon?</h3>

Hydrocarbon is defined as the compound which contain hydrocarbon and carbon atoms.

The carbon atom attached to each other to form framework and hydrogen atom attach to them in different ways to give different configuration. One of the most popular hydrocarbon compound is diamond.

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