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melisa1 [442]
2 years ago
6

A reaction rate increases by a factor of 655 in the presence of a catalyst at 37°C. The activation energy of the original pathwa

y is 106 kJ/mol. What is the activation energy of the new pathway, all other factors being equal? Group of answer choices 89.3 kJ/mol 16,600 kJ/mol 89.3 J/mol 16,600 J/mol
Chemistry
1 answer:
irinina [24]2 years ago
5 0

For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway  is mathematically given as

Ea2=89.28JKoule/mol

<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>

Generally, the equation for the rate constant  is mathematically given as

K=Ae^{Ea1/Rt}

Therefore

\frac{1}{655}=\frac{1}{8.31*3.10}(Ea2-105000)

Ea2=89286.083Joule/mol

In conclusion, the activation energy

Ea2=89.28JKoule/mol

Read more about Energy

brainly.com/question/13439286

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