Which of the following situations most likely indicates the lowest relative humidity? situation A situation B situation C situat
2 answers:
You might be interested in
Answer: 1. C. polar covalent: electrons shared between silicon and sulfur but attracted more to the sulfur
2. B)
3. B) Fluorine
Explanation:
1. A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.
Electronegativity difference = electronegativity of sulphur- electronegativity of silicon = 2.5 -1.8 = 0.7
Thus as electronegativity difference is less than 1.7 , the cond is polar covalent and as electronegativity of sulphur is more , the electrons will be more towards sulphur.
2. A molecular compound is usually composed of two or more nonmetal elements. Example:
Ionic compound is formed by the transfer of electrons from metals to non metals. Example: ,
and
3. For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here K is having an oxidation state of +1 and as the compound formed is KZ, the oxidation state of non metallic element Z should be -1. Thus the element Z is flourine which exists as diatomic gas
<u>First of all, what is electrolysis?</u>
Electrolysis is the process of breaking down ionic substances using direct current.
<u>Important points about electrolysis </u>
→ Ionic substances contain particles called ions.
→ Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions. The ions must be free to move for electrolysis to occur and it can happen by melting or dissolving an ionic substance in water.
→ Positively charged ions move to the negative electrode. They receive electrons and are <em>reduced</em>. The positive ions move towards the negative electrode because they want to cancel each other out.
→ Negatively charged ions move to the positive electrode. They lose electrons and are <em>oxidised</em>. The substance that is broken down is called the electrolyte <em>(an electrolyte is just a liquid or solution that can conduct electricity)</em> . The negative ions move towards the positive electrode because they want to cancel each other out.
<h3>Cathode = Negative electrode</h3><h3>Anode = Positive electrode</h3>Metal ions form at the cathode and non-metal ions form at the anode
How I remember if an element is <em>oxidised</em> or <em>reduced</em> is by remembering OIL RIG
OIL = Oxidation is Loss (of electrons)
RIG = Reduction is Gain (of electrons)
<h2><em><u>The answer to your question</u></em></h2>1) The first step would be to clean the metal ring and sand it down because when the metal atoms from the electrolyte are deposited onto the ring, they will form a weak bond and they may simply 'fall' off. Also this could affect conductivity and the whole experiment. The more things you do accurately now, the more accurate your result will be.
2) You want to put the solution you are given in to the tank your going to be using.
3) This is basically the main part, you want to set up the circuit, I have attached a diagram at the bottom to show you the circuit. The copper rod will be the anode and the metal ring will be a cathode (ignore the elements).
4) Now turn on the circuit and you will start to see the solution spilt with the the solution now being split some going to the anode and some going the cathode.
5) Then a thin layer should form on the electrode.
Hope this helps :)
<h2><em><u></u></em></h2><em><u></u></em>
